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3 years ago

How do you solve, y - 5 =-8 ?

1 answer:

5 0

To solve, you would first take the equation y-5=-8, and add 5 on each sides. (To solve an equation, you need to isolate the variables. Adding 5 on both sides will cancel out the "- 5". in order to do this you must do it to both sides so it will still be even.) You should now have Y = -3. to check this, you can say "-3 - 5 =", and your answer will be -8.

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So $n = 6, s = \frac{106}{\sqrt{6}} = 43.27$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 523}{43.27}$

$Z = -2.61$

$Z = -2.61$ has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0

3 years ago

What’s the answer pleazzzzz helplllllll 9m^2-4m-6 by 3m

dlinn [17]

Answer

D. 3m - 4/3 -2/m

Explanation

(9m²-4m-6) ÷ 3m = 9m²/3m - 4m/3m - 6/3m

Carry out the division, each term is divided by 3m.

9m²/3m = 3m

- 4m/3m = -4/3

- 6/3m = - 2/m

Finally you will get,

3m - 4/3 -2/m

5 0

3 years ago

Given that mzAOB = 131/18 and the radius is 8 cm, what is the length of arc AB?

avanturin [10]

Answer:

uun

Step-by-step explanation:

kfqhacz

6 0

2 years ago

What is the answer to 76?

vovangra [49]

Answer:

13.2 minutes or 13 minutes 12 seconds.

Step-by-step explanation:

1. Count how much water drains the first pump every minute. Let the volume of pool be D. Every minute first pump drains D/11 water.

2. Working together(6 minutes) First pump drains 6D/11 water, hence the second pump drains 5D/11 water.

3.Count how much water drains second pump per minute -> (5D/11)/6= 5D/66

4. It takes the second pump 66 minutes to drain pool 5 times, thus it takes 13.2(66/5) minutes to drain the pool, which is 13 minutes 12 seconds.

7 0

3 years ago

The base of a juice glass is in the shape of a circle

antoniya [11.8K]

The answer is going to be c

5 0

3 years ago