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3 years ago

What series of transformations to quadrilateral ABCD map the quadrilateral onto quadrilateral EFGH to prove that ABCD≅EFGH ?

Mathematics

1 answer:

iris [78.8K]3 years ago

4 0

For this case we have the following transformation rule:
(x, y) --------> (x, - y - 2) ----------> (x ', y')
We are going to apply the following transformation rule for vertex D, for example.
We have then:
(4, 1) --------> (4, - 1 - 2) ----------> (4, -3)
Therefore, the transformation is:
Reflection on the x axis and vertical displacement 2 units down.
Answer:
a reflection across x-axis, and then a translation 2 units down

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Natalija [7]

Answer:

Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.

Step-by-step explanation:

We know that:

48 + 8(b) = Carly's expenditure
10(b) = Carly's expenditure
48 + 8b = 10b
B = Boxes of cards

Work:

48 + 8b = 10b
=> 48 + 8b - 8b = 10b - 8b
=> 48 = 2b
=> b = 24

Now, let's substitute the value of b into any equation.

10(24)
=> 240

Hence, Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.

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3 years ago

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3 years ago

It is estimated that 3% of the athletes competing in a large tournament are users of an illegal drug to enhance performance. The

yuradex [85]

Answer:

probability that an athlete who tests positive is actually a user

= 0.2177

Step-by-step explanation:

To solve this problem, we create a table that relates the test results and the status of the athletes.

We arbitrarily take a sample of 10000 atheletes to work with whole numbers.

Out of that, 300 are users (3% on the average), and 9700 are non users.

Of the users, 270 users will test positive (90% accuracy) and 30 will test negative.

Similarly, of the non-users, 970 will test positive, and 8730 will test negative.

This gives 1240 positive tests, and 8760 negative tests.

Of the 1240 who test positive, 270 are actually users.

Therefore the probability of the positive test results are actually users

= 270/1240 = 0.2177

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4 years ago

What series of transformations to quadrilateral ABCD map the quadrilateral onto​ quadrilateral EFGH ​ to prove that ABCD≅EFGH ?

What series of transformations to quadrilateral ABCD map the quadrilateral onto quadrilateral EFGH to prove that ABCD≅EFGH ?