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drek231 [11]
3 years ago
13

If you know that a system of linear equations has at least two? solutions, how many solutions must it actually? have? explain.

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0
A linear equation will only have one solution, no solutions, or infinite solutions.

so if it has at least two solutions, then it actually has infinite solutions
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Using the slope formula, determine the slope of the two points.
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The slope formula is is rise over run or y2-y1/x2-x1

If you plug in those numbers you will get

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———
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Estimate the answer from the table or graph. The number of calories in different food items are given below. If Jeanne had a ser
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Which statement is modeled by the expression?
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A librarian has 150 books to be placed on shelves with an equal number of books on each shelf. If k is the number of shelves to be used, then 150/k is the number of books on each shelf.

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4 0
3 years ago
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Help on 3. And 4. Thank you!
chubhunter [2.5K]

Answer:

#3.) The initial value of  16 gal at  x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.

#4.) Find how many minutes until the barrel is empty of water.

Let y = 0,  to solve for time x.

0 = (-2/5)*x + 18

(2/5)*x = 18

x = (5/2)* 18 = 5*9 = 45 minutes

Up to and after 45 minutes, the barrel is empty of water.

Step-by-step explanation:

#2.)  

minutes:      5, 10, 15, 20

water(gal):  16, 14, 12, 10

Find slope:    slope m = (14 - 16)/(10 - 5) = -2/5

y - 10 = (-2/5)*(x - 20)

y - 10 = (-2/5)* x  + 8

y = (-2/5)*x + 18

rate of change slope means that for every minute  2/5 gallons of water is lost

#3.) The initial value of  16 gal at  x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.

#4.) Find how many minutes until the barrel is empty of water.

Let y = 0,  to solve for time x.

0 = (-2/5)*x + 18

(2/5)*x = 18

x = (5/2)* 18 = 5*9 = 45 minutes

4 0
4 years ago
Use the quadratic function f(x) = 2x^2 + 4x - 15. Find any x intercepts.
8_murik_8 [283]

So for this function we will be using the quadratic formula, which is x=\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a} , to solve. a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation, we can solve for the zeros (x-intercepts) as such:

x=\frac{-4+\sqrt{4^2-4*2*(-15)}}{2*2},\frac{-4-\sqrt{4^2-4*2*(-15)}}{2*2}\\ \\ x=\frac{-4+\sqrt{16-(-120)}}{4},\frac{-4-\sqrt{16-(-120)}}{4}\\ \\ x=\frac{-4+\sqrt{136}}{4},\frac{-4-\sqrt{136}}{4}\\ \\ x=1.92,-3.92

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).

6 0
4 years ago
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