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Lyrx [107]
3 years ago
9

How many moles of tin atoms are in a pure tin cup with a mass of 37.6 g ?

Chemistry
1 answer:
Georgia [21]3 years ago
3 0
Tin is an element called Stannum and has the symbol Sn. Molar mass is the mass of 1 mol of a compound, 1 mol of any substance is made of 6.022 x 10²³ units, these units could be atoms making up an element or molecules making up a compound. 
While the number of atoms making up 1 mol is the same for any element, the weight of 1 mol of substance varies from one another.
In tin(Sn) molar mass - 118.71 g/mol
In 118.71 g - there's 1 mol of tin
therefore in 37.6 g of tin - 1 x 37.6 / 118.71 = 0.31 mol 
In 37.6 g of tin, there's 0.31 mol 
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Nuclear fusion is a process in which atomic nuclei are fused together to form heavier nuclei. ... Like fission, nuclear fusion can also transmute one element into another. For example, hydrogen nuclei fuse in stars to form the element helium.

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Which electron configuration represents the electrons of an atom in an excited state? * 2-3 2-7-1 2-8 2-8-1​
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2-7-1

<h3>Further explanation </h3>

Electrons can move the shell up or down by releasing energy or absorbing energy  

Excited electrons show higher electron transfer to the shell by absorbing energy  

So it can be concluded that there are 2 conditions:  

Ground state is the state of electrons filling shell with the lowest energy levels.  

Excited state is the state of electrons which occupies a higher energy level  

The state of excited electrons can be seen from the presence of electrons which do not fill the skin completely but fill the skin afterward  

2-7-1

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the electrons in the third shell should fill the electrons in the second shell first according to Aufbau rule (lower energy shells)

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3 years ago
A 5.00g of X, the product of organic synthesis is obtained in a 1.0 dm3 aqueous solution. Calculate the mass of X that can be ex
Anestetic [448]

Answer:

mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

Explanation:

The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula

K = concentration of X in ether/concentration of X in water

Partition coefficient, K(X) between ethoxy ethane and water = 40

Concentration of X in ether = mass(g)/volume(dm³)

Mass of X in ether = m g

Volume of ether = 50/1000 dm³ = 0.05 dm³

Concentration of X in ether = (m/0.05) g/dm³

Concentration of X in water = mass(g)/volume(dm³)

Mass of X in water left after extraction with ether = (5 - m) g

Volume of water = 1 dm³

Concentration of X in water = (5 - m/1) g/dm³

Using K = concentration of X in ether/concentration of X in water;

40 = (m/0.05)/(5 - m)

(m/0.05) = 40 × (5 - m)

(m/0.05) = 200 - 40m

m = 0.05 × (200 - 40m)

m = 10 - 2m

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m = 10/3

m = 3.33 g of X

Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

8 0
3 years ago
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