1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zarrin [17]
2 years ago
7

What is the group of elements with the same number of valence electrons?

Chemistry
1 answer:
Leya [2.2K]2 years ago
7 0

Answer:

All groups have the same number of valence electrons.

Explanation:

groups are the columns.

You might be interested in
Which statement is not true?
ludmilkaskok [199]
B) some planets revolve backwards

3 0
3 years ago
Anyone know the answer
kodGreya [7K]

Answer:

a and d

Explanation:

a bromine and the calcium atom loses two elections

6 0
3 years ago
Choose all answers that apply
Alexeev081 [22]

Answer

Rapid Combustion

Explanation:

An explosion is a combustion and a quick reaction, That makes it rapid

3 0
2 years ago
Read 2 more answers
A beaker with 1.60×102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and c
stich3 [128]

Answer:

The pH will change 0.16 ( from 5.00 to 4.84)

Explanation:

Step 1: Data given

volume of acetic acid buffer = 160 mL

The total molarity of acid and conjugate base in this buffer is 0.100 M

A student adds 7.10 mL of a 0.460 M HCl solution to the beaker.

The pKa of acetic acid is 4.740

pH = 5.00

Step 2: Calculate concentration of acid

Consider x = concentration acid

Consider y = concentration conjugate base

x + y = 0.100

5.00 = 4.740 + log y/x

5.00 - 4.740 = log y/x

0.26 = log y/x

10^0.26 =1.82 = y/x

1.82 x = y

Since x+y = 0.100

x + 1.82 x = 0.100

2.82 x = 0.100

x =0.0355 M = concentration acid

Step 3: Calculate concentration of conjugate base

y = 0.100 - x

0.100 - 0.0355 =0.0645 M= concentration conjugate base

Step 4: Calculate moles of acid

Moles = volume * molarity

moles acid = 0.160 L * 0.0355 M= 0.00568  moles

Step 5: Calculate moles of conjugate base

moles conjugate base = 0.0645 M * 0.160 L=0.01032 moles

Step 6: Calculate moles HCl

moles HCl = 7.10 * 10^-3 L * 0.460 M=0.003266 moles

Step 7: Calculate new moles

A- + H+ = HA

moles conjugate base = 0.01032 - 0.003266 =0.007054  moles

moles acid = 0.00568 + 0.003266=0.008946 moles

Step 8: Calculate the total volume

total volume = 160 + 7.10 = 167.1 mL = 0.1671 L

Step 9: Calculate the concentration of the acid

concentration acid = 0.008946/ 0.1671 =0.0535 M

Step 10: Calculate the concentration of conjugate base

concentration conjugate base = 0.007054/ 0.1671 =0.0422 M

Step 11: Calculate the pH

pH = 4.740 + log 0.0535/ 0.0422=4.84

change pH = 5.00 - 4.84=0.16

The pH will change 0.16

5 0
3 years ago
How many carbon atoms are in 26-hydrogen alkyne
navik [9.2K]
An alkyne contains four carbon atoms.... so if you do 26 multiplied by 4 it equals 104... I do not know if that’s the answer so I apologize if it’s wrong :,)
5 0
3 years ago
Other questions:
  • IM GIVING 30 POINTS PLUS BRAINLIEST FOR CORRECT ANSWERS !!!
    11·2 answers
  • The alkali metal that is naturally radioactive is ________.
    8·1 answer
  • The mass number of Fez is 56. How many neutrons are there in a single Fez atom?
    6·1 answer
  • 73.5 grams C, 4.20 grams H, and 72.3 grams Cl. What is the percent composition of each element in this compound?
    12·1 answer
  • In aqueous solution the Ni2" ion forms a complex with four ammonia molecules. Write the formation constant expression for the eq
    5·1 answer
  • 3) In which system do molecule-ion attractions
    11·1 answer
  • Please help!!!!! i dont really know what the subject is so-
    5·1 answer
  • Which of the following is true about electrostatic forces? Check all that are true:
    11·1 answer
  • Please help!!! will give 25 points!
    13·1 answer
  • If you add sucrose to catalase when testing for reactivity, do you expect to see a reaction?.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!