1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ohaa [14]
3 years ago
9

Perform all indicated operations, and express each answer in simplest form with positive exponents. Assume that all variables re

present positive real numbers. Have to show all work.

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

a. -( 4\sqrt{3} + 3)

b.  x^{\frac{-5}{12}} y^{\frac{31}{24}}

c.  \frac{8\sqrt{x} + 8\sqrt{5}}{x - 5}

d. 45 + 12\sqrt{5y} + 4 y

e. -(\frac{3}{5x})^{\frac{1}{2}}

Step-by-step explanation:

a.

\sqrt{12} - \sqrt{108} - \sqrt[3]{27}

Expand each expression

\sqrt{4*3} - \sqrt{36 * 3} - \sqrt[3]{3*3*3}

Split the first two surds

\sqrt{4}*\sqrt{3} - \sqrt{36} * \sqrt{3} - \sqrt[3]{3*3*3}

2*\sqrt{3} - 6 * \sqrt{3} - \sqrt[3]{3*3*3}

Apply law of indices

2*\sqrt{3} - 6 * \sqrt{3} - \sqrt[3]{3^3}

Apply law of indices

2*\sqrt{3} - 6 * \sqrt{3} - 3^{3*\frac{1}{3}}

2*\sqrt{3} - 6 * \sqrt{3} - 3^{1}

2*\sqrt{3} - 6 * \sqrt{3} - 3

2\sqrt{3} - 6\sqrt{3} - 3

- 4\sqrt{3} - 3

Factorize

-( 4\sqrt{3} + 3)

<em>The expression cannot be further simplified</em>

b.

(\frac{x^{\frac{-3}{4}}y^{\frac{2}{3}}}{x^{\frac{-1}{3}}y^{\frac{-5}{8}}})

Expand the expression

(\frac{x^{\frac{-3}{4}} * y^{\frac{2}{3}}}{x^{\frac{-1}{3}} * y^{\frac{-5}{8}}})

Apply the following law of indices;

\frac{a^m}{a^n} = a^{m-n}

x^{{\frac{-3}{4} - \frac{-1}{3}}} * y^{{\frac{2}{3} - \frac{-5}{8}}}}

x^{{\frac{-3}{4} + \frac{1}{3}}} * y^{{\frac{2}{3} + \frac{5}{8}}}}

Add the exponents

x^{\frac{-9+4}{12}} * y^{{\frac{16+15}{24}}}}

x^{\frac{-5}{12}} * y^{{\frac{31}{24}}}}

x^{\frac{-5}{12}} y^{\frac{31}{24}}

<em>The expression cannot be further simplified</em>

c.

\frac{8}{\sqrt{x} - \sqrt{5}}

Rationalize the denominator

\frac{8}{\sqrt{x} - \sqrt{5}} * \frac{\sqrt{x} + \sqrt{5}}{\sqrt{x} + \sqrt{5}}

\frac{8(\sqrt{x} + \sqrt{5})}{(\sqrt{x} - \sqrt{5})(\sqrt{x} + \sqrt{5})}

Simplify the numerator

\frac{8\sqrt{x} + 8\sqrt{5}}{(\sqrt{x} - \sqrt{5})(\sqrt{x} + \sqrt{5})}

Simplify the denominator by difference of two squares

\frac{8\sqrt{x} + 8\sqrt{5}}{\sqrt{x}^2 - \sqrt{5}^2}

\frac{8\sqrt{x} + 8\sqrt{5}}{x - 5}

<em>The expression cannot be further simplified</em>

<em></em>

d.

(3\sqrt{5} + 2\sqrt{y})^2

Expand the expression

(3\sqrt{5} + 2\sqrt{y})(3\sqrt{5} + 2\sqrt{y})

Open the bracket

3\sqrt{5} (3\sqrt{5} + 2\sqrt{y})+ 2\sqrt{y}(3\sqrt{5} + 2\sqrt{y})

Open both brackets

3\sqrt{5} *3\sqrt{5} + 3\sqrt{5}*2\sqrt{y}+ 2\sqrt{y}*3\sqrt{5} + 2\sqrt{y}*2\sqrt{y}

(3\sqrt{5} *3\sqrt{5}) + (3\sqrt{5}*2\sqrt{y})+ (2\sqrt{y}*3\sqrt{5}) + (2\sqrt{y}*2\sqrt{y})

Multiply each expression in the bracket

(3*3\sqrt{5*5}) + (3*2\sqrt{5*y})+ (2*3\sqrt{5*y}) + (2*2\sqrt{y*y})

(9\sqrt{25}) + (6\sqrt{5y})+ (6\sqrt{5y}) + (4\sqrt{y^2})

Solve like terms

(9\sqrt{25}) + (12\sqrt{5y}) + (4\sqrt{y^2})

Take square root of 25 and y²

(9 * 5) + (12\sqrt{5y}) + (4 * y)

(45) + (12\sqrt{5y}) + (4 y)

Remove the brackets

45 + 12\sqrt{5y} + 4 y

<em>The expression cannot be further simplified</em>

e.

-\sqrt{\frac{3}{5x}}

This expression can not be simplified; However, it can be rewritten, by applying law of indices as

-(\frac{3}{5x})^{\frac{1}{2}}

You might be interested in
What is 6/54 equivalent to
Ann [662]
0.1111 if you want it as a decimal
3 0
2 years ago
Read 2 more answers
Give the domain and range.
alexgriva [62]

Answer:

c. domain: {-2, 0, 2}, range: {-1, 1, 3}

Step-by-step explanation:

Given:

There are three points on the graph.

Locate the x and y values of the points on the graph.

The points are (-2,-1),(0,1),\textrm{ and }(2,3)

Domain is the set of all possible x values. Here, the x values are -2, 0 and 2.

So, domain is: {-2, 0, 2}.

Range is set of all possible y values. Here, the y values are -1, 1 and 3.

So, range is: {-1, 1, 3}

7 0
2 years ago
Which of the following describes the transformation from Figure 1 to Figure 2?​
12345 [234]

Answer:

hi figure 1 is mentioning stuff about trigonomatry ratios

Step-by-step explanation:

6 0
2 years ago
Plz help the question is so confusing!!
gizmo_the_mogwai [7]

Answer:

-2

Step-by-step explanation:

because the slope is 2, a perpendicular line must be the inverse  

the equation for y1 is y=2x+1

y2= -2y+1

5 0
3 years ago
Read 2 more answers
Prove that 1+cosA/sinA + sinA/1+cosA=2cosecA
Alla [95]
\frac{1+cos\alpha}{sin\alpha}+\frac{sin\alpha}{1+cos\alpha}=2cosec\alpha\\\\L=\frac{(1+cos\alpha)(1+cos\alpha)+sin\alpha\cdot sin\alpha}{sin\alpha(1+cos\alpha)}=\frac{1+2cos\alpha+cos^2\alpha+sin^2\alpha}{sin\alpha(1+cos\alpha)}\\\\=\frac{1+2cos\alpha+1}{sin\alpha(1+cos\alpha)}=\frac{2+2cos\alpha}{sin\alpha(1+cos\alpha)}=\frac{2(1+cos\alpha)}{sin\alpha(1+cos\alpha)}\\\\=\frac{2}{sin\alpha}=2\cdot\frac{1}{sin\alpha}=2cosec\alpha=R
5 0
3 years ago
Other questions:
  • Round to the nearest whole number: 67.24
    7·1 answer
  • Express in decimal notation. 1.56 × 10^−4
    13·2 answers
  • On a very cold morning, it was -8°F. As the day went on the temperature rose 2
    10·1 answer
  • 20. Rectangle ABCD is transformed to create rectangle EFGH. What sequence of
    13·1 answer
  • Is the value of the 3 in 83.47 is 1/10 the value of the 3 in 95.33 true or false
    11·1 answer
  • a manufacturer is designing a new container for their chocolate-covered almonds. Their original container was a cylinder with th
    10·1 answer
  • If the circle below is cut from the square of plywood below, how many square inches of plywood would be left over? Use π = 3.14,
    8·1 answer
  • There are 5 gray, 4 red, 5 white, 2 green, and 2 navy marbles in a hat. Two marbles are
    14·2 answers
  • <img src="https://tex.z-dn.net/?f=%5Csqrt%7B89" id="TexFormula1" title="\sqrt{89" alt="\sqrt{89" align="absmiddle" class="latex-
    12·2 answers
  • HURRRY I HAVE 5 minutes! WILL GIVE BRAINLIEST
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!