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Mars2501 [29]
3 years ago
9

Vector v has a direction of (-4,27) find the direction angle for v

Mathematics
1 answer:
mixas84 [53]3 years ago
8 0
\bf \begin{array}{lclll}
\ \textless \ &-4&,&27\ \textgreater \ \\
&\uparrow &&\uparrow \\
&a&&b
\end{array}\qquad tan(\theta)=\cfrac{b}{a}\implies \measuredangle \theta=tan^{-1}\left( \frac{b}{a} \right)
\\\\\\
\measuredangle \theta=tan^{-1}\left( \frac{27}{-4} \right)
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6 0
3 years ago
Please select the best answer.
Amiraneli [1.4K]

ANSWER

C. The left end goes up; the right end goes down.

EXPLANATION

The given function is

f(x) =  - 2( {x - 2)}^{5}

We analyze the end behavior of this function using the leading term.

The leading term of this function is:

- 2 {x}^{5}

Since the degree(5) is odd and the leading coefficient (-2) is negative, the graph rises on the left and falls on the right.

In other words, the left end of the graph goes up and the right end goes down.

The correct option is C.

5 0
3 years ago
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Salsk061 [2.6K]

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Step-by-step explanation:

8 0
3 years ago
Having trouble with this one can somebody help?
Varvara68 [4.7K]
Form equation
y = mx + c
y = (rise/run).x + c
y = (11-1 / 3--2)x + c
y = 2x + c
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Find c (y-intercept)
11 - 6 = c
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Substitute given possible x-values in to find y-values
y = 2(1) + 5 = 7 (1,7)
y = 2(2) + 5 = 9 (2,9)
Therefore d is correct
3 0
3 years ago
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