A = nuts of $2/lb
B = nuts of $7/lb
let's say we'll mix "x" lbs of B to get a mixture with A of "y" lbs, therefore

Answer:
Option D
Step-by-step explanation:
Given expression has been given as,
![\sqrt[5]{224x^{11}y^8}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D)
![\sqrt[5]{224x^{11}y^8}=\sqrt[5]{2\times 2\times 2\times 2\times 2\times 7(x^{11})(y^8)}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D%3D%5Csqrt%5B5%5D%7B2%5Ctimes%202%5Ctimes%202%5Ctimes%202%5Ctimes%202%5Ctimes%207%28x%5E%7B11%7D%29%28y%5E8%29%7D)
![=\sqrt[5]{(2^5)\times (7)(x^{10}\times x)(y^5\times y^3)}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B5%5D%7B%282%5E5%29%5Ctimes%20%287%29%28x%5E%7B10%7D%5Ctimes%20x%29%28y%5E5%5Ctimes%20y%5E3%29%7D)


![=2x^2y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=%3D2x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Option D will be the answer.
Answer:
B will be the answer...
Step-by-step explanation:
The second equation in system B is only in terms of y, so we need to use elimination to eliminate the x term from the second equation in system A.
To do that, we need to multiply the first equation by 5.
5 (-x − 2y = 7)
-5x − 10y = 35
Add to the second equation. Notice the x terms cancel out.
(-5x − 10y) + (5x − 6y) = 35 + (-3)
-16y = 32
Combining this new equation with the first equation from system A will get us system B.
-x − 2y = 7
-16y = 32
I'm sorry hun, i suck at math. If i knew how i would help you. Have you tried looking it up?