Answer:
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Explanation:
The frequency of choice-3 is
(3 x 10⁸ m/s) / (500 m) = 600,000 Hz.
That number is the 600 near the bottom of the AM radio dial.
To solve this problem we will apply the concepts related to the relationship between the voltage, the electric field and the distance, once the voltage is found we will use the definition of power, which is defined as the square of the voltage over the resistance. This is,

E = Electric field
d= Distance between the points
Replacing,


Now applying the relation for power we have,

Here
V = Voltage
R = Resistance
Replacing,


Therefore the total power emmited by the transmitter is 224509.3 W
Answer:
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Answer:
The value of capillary rise in the tube = 0.0363 cm
Explanation:
Diameter of the glass tube = 0.03 meter
Contact angle = 22 degree
We know that the capillary rise (h) in the tube is given by the formula =
h = (2 α cos β) / (d g R )
⇒ d = density of gasoline = 749 kg / 
β = 22 degree
R = radius of the tube = 0.015 m
α = surface tension of gasoline = 0.0216 N / m
cos 22 = 0.927
Put all the values in the above formula we get
⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)
⇒ h = 0.0363 cm
This is the value of capillary rise in the tube.