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ankoles [38]
3 years ago
14

CDEF is a kite and FCE = 34 . Find m1.

Mathematics
1 answer:
klio [65]3 years ago
4 0

<FCE = 34

<1 = <FCE = 34

34Therefore angle 1=44

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right angle?

Step-by-step explanation:

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Which shows a correct order to solve this story problem?
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C is the right answer, the product is 13.348
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Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in
tatuchka [14]

Answer:

The equation representing how old Monique son is \mathbf{a = 2 + \dfrac{8}{21}(q-34)}

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

q(t) = \hat q \times t + q_o

where;

q_o = initial height of Monique's son

\hat q = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

\hat q = 2 \dfrac{5}{8} \ in/yr

\hat q =  \dfrac{21}{8} \ in/yr

Then; from the equation q(t) = \hat q \times t + q_o

34 = \dfrac{21}{8} \times 0 + q_o

q_o = 34\  inches

The height of the son as a function of the age can now be expressed as:

q(t) = \dfrac{21}{8} \times t + 34

Then:

Making t the subject;

q - 34 = \dfrac{21}{8} \times t

t = \dfrac{8}{21}(q-34)

and the age of the son  i.e. ( a (in years)) is:

a = 2 + t

So;

\mathbf{a = 2 + \dfrac{8}{21}(q-34)}

SO;

if q (growth rate) = 50 inches tall

Then;

\mathbf{a = 2 + \dfrac{8}{21}(50-34)}

\mathbf{a = 2 + \dfrac{8}{21}(16)}

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

8 0
2 years ago
An online furniture store sells chairs for $50 each and tables for $550 each. Every day, the store can ship a maximum of 32 piec
Hunter-Best [27]

Answer:

you have to sell 6 tables to meet all requirements

Step-by-step explanation:

chairs=$50x

tables=$550x

24 chairs×50= $1200

4100-1200= $2900

take $2900 and divide by $550 to find the exact number of tables which is 5 but selling 5 tables and 24 chairs doesnt reach the $4100 mark so I rounded up to 6 tables which doesnt surpass the maximum number of furniture(32) but beats the $4100 mark

3 0
3 years ago
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