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3 years ago

Someone tells you that scientific knowledge cannot be changed or modified. How would you answer this statement?

1 answer:

8 0

Scientific knowledge can be modified. This is because all the scientific principles that are existing now is not certain for all possible conditions. Scientific knowledge is not directly given to us, human minds work the effort of unveiling the unknown. Thus, scientists are slowly discovering the science of all natural phenomena. Along the way, they could come up with misinterpretations. Let me give a concrete example. When J.J. Thompson proposed the Plum-Pudding model, it was the widely accepted theory in the field of atomic science. However, when Rutherford did his golden foil experiment, he disproved Thompson's model and proposed the Planetary Model. Therefore, scientific knowledge is an ongoing process. Scientists would always want to disprove each other, not because they want to compete with each other. They want to discover the truth together with what they have to the best of their abilities. They are never content with just one simple principle according to one scientist. It will always be verified by a group of fellow scientists.

In the 21st century where technology is exponentially progressing, scientists would discover more of the basic principles. Hence, we would expect that scientific knowledge is constantly changing and modifying.

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A 15.0 Kg object is moved from a height of 7.00 m above thefloor to a height of 13.0 m above the floor. What is the change ingra

Pie

To solve this problem we will apply the concepts related to potential gravitational energy. This is defined as the product between mass, acceleration and change in height and can be expressed as,

$\Delta PE = mg \Delta h$

Here,

m = Mass

g = Gravitational acceleration

$\Delta h$ = Height

Replacing with our values we have,

$\Delta PE = (15kg)(9.81m/s^2)(13m-7m)$

$\Delta PE = 882.9J \approx 883J$

Therefore the change in gravitational potential energy is 883J.

4 0

3 years ago

As you travel from Detroit in a certain direction, the outside temperature, T (in degrees), depends on your distance, d (in mile

Ber [7]

Answer:

a) $\Delta T= 100^{\circ}C$

b) $\bigtriangledown T=1^{\circ}C.mile^{-1}$

c) $\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

d) $\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

Explanation:

Given is the data of variation of temperature with respect to the distance traveled:

Temperature T as a function of distance d:

$T=(d+30) ^{\circ}C$ ...................................(1)

(a)

Total change in temperature from the start till the end of the journey:

$\Delta T= T_f-T_i$ ..............................(2)

where:

$T_f$ = final temperature

$T_i$ = initial temperature

∵In the start of the journey d = 0 miles & at the end of the journey d = 100 miles.

So, correspondingly we have the eq. (2) & (1) as:

$\Delta T= (100+30)-(0+30)$

$\Delta T= 100^{\circ}C$

(b)

Now, the average rate of change of the temperature, with respect to distance, from the beginning of the trip to the end of the trip be calculated as:

$\bigtriangledown T=\frac{\Delta T}{\Delta d}$ ......................(3)

where:

$\Delta d$ = change in distance

$\bigtriangledown T=$ change in temperature with respect to distance

putting the respective values in eq. (3)

$\bigtriangledown T=\frac{100}{100}$

$\bigtriangledown T=1^{\circ}C.mile^{-1}$

(c)

comparing the given function of the temperature with the general equation of a straight line:

$y=m.x+c$

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

$\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

(d)

comparing the given function of the temperature with the general equation of a straight line:

$y=m.x+c$

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

$\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

4 0

4 years ago

Different color ca

777dan777 [17]

Answer: The color of candy cane

Explanation:

An independent variable is the Variable that the scientist changed in order to change the dependent variable. The scientist changes the color of the candy cane to test the rate at which they dissolve.

4 0

4 years ago

What is the forward velocity of a 250 lb stone projectile that leaves a medieval catapult 55 degrees from the ground at 50 m/s?

OLga [1]

Answer:

28.5 m/s

Explanation:

The speed has two orthogonal components, horizontal and vertical. To decompose the speed into these components we can use these trigonometric equations:

Vh = V * cos(a)

Vv = V * sin(a)

The forwards velocity is the horizontal component, so we use

Vh = V * cos(a)

Vh = 50 * cos(55)

Vh = 50 * 0.57

Vh = 28.5 m/s

6 0

4 years ago

A cran uses an average force of 5200N to lift a steel beam 25m. How much work does the crane do on the steal beam.

Aliun [14]

The work done by a force is given by:
$W=Fd \cos \theta$
where
F is the magnitude of the force
d is the distance covered by the object
$\theta$ is the angle between the direction of the force and the direction of motion

In our problem, $F=5200 N$ , $d=25 m$ and $\theta=0$ (because the force is parallel to the direction of motion), so the work done by the crane is
$W=(5200 N)(25 m)(\cos 0^{\circ})=1.3 \cdot 10^5 J$

8 0

3 years ago