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vladimir1956 [14]
3 years ago
12

Bob read data from the projectile motion lab graph shown and determined that the drop time was inversely proportional to the hor

izontal velocity. Which of the following statements is true?
Bob's conclusion was wrong because the x-axis scale is exaggerated.

Bob's conclusion was right because the data points were connected.

Bob's conclusion was wrong because the y-axis scale is exaggerated.

Bob's conclusion was right because the x-axis scale is exaggerated.,
Physics
2 answers:
Amiraneli [1.4K]3 years ago
7 0

Answer:

bobs conclusion was wrong because the y-axis scale is exaggerated

Explanation:

I just took the test and got it right.

Alecsey [184]3 years ago
3 0
When he <span>determined that the drop time was inversely proportional to the horizontal velocity, the answer for it would be </span>Bob's conclusion was right because the data points were connected.  The connection of the x and y axis varied  because it is inversely proportional.
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The sun's energy is stored in fossil fuels. true or false.
Scilla [17]
Yes,suns original energy are still stored at the bonds of fossils in which they taken long,long time ago and these fossils powered now industries,fuel for vehicles.In those chemical bonds holds much energy packed together for centuries.
8 0
3 years ago
A 30kg boxed is pushed with a force of 20N. What is the boxes acceleration. Please show work
kozerog [31]

Answer:

<h3>The answer is 0.67 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{20}{30}  =  \frac{2}{3}  \\  = 0.6666666...

We have the final answer as

<h3>0.67 m/s²</h3>

Hope this helps you

8 0
3 years ago
A sphere of radius r = 5cm carries a uniform volume charge density rho = 400 nC/m^3. Q. What is the total charge Q of the sphere
Tanzania [10]

Answer:

The total charge Q of the sphere is 2.094\times10^{-10}\ C.

Explanation:

Given that,

Radius = 5 cm

Charge density J= 400\ nC/m^3

We need to calculate the total charge Q of the sphere

Using formula of charge

q=\rho V

Where, \rho = charge density

V = volume

Put the value into the formula

q=\rho\times(\dfrac{4}{3}\pi r^3)

Put the value into the formula

q=\dfrac{4}{3}\times\pi\times400\times10^{-9}\times(5\times10^{-2})^3

q=2.094\times10^{-10}\ C

Hence, The total charge Q of the sphere is 2.094\times10^{-10}\ C.

6 0
3 years ago
Help !
Black_prince [1.1K]
First off, you need to know the weight of the projectile, lift and drag coefficients something like a high Reynolds number is preferred, then use the gravitational constant of 9.8 meters per second squared those would be a good start to get closer to your goal
7 0
4 years ago
Future space stations could create an artificial gravity by rotating. Consider a cylindrical space station that rotates with a p
aleksandrvk [35]

Answer:

P = 2 pi R / v    period of space station

F / m = v^2 / R    centripetal force per unit of mass

So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2

Also, F / m = 9.8 m/s^2   earth's gravitational attraction

So 9.8 = 4 pi^2 R / P^2    or    R = 9.8 P^2 / 4 * pi^2) = 195 m

Or D = 2 R = 390 m the diameter required

8 0
3 years ago
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