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anzhelika [568]
3 years ago
5

Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms

as levers. Which statement describes this as a class three lever?
Question 13 options:

The wood in your hands was the fulcrum, the load your elbow, and the effort (input force) was supplied by your arm muscles.


The wood was the load in your hands, the fulcrum was your elbow and the effort (input force was supplied by your arm muscles.


The fulcrum was the muscles in your arms, the load was the wood in your hands and the effort (input force) was the elbow.
Physics
2 answers:
Evgesh-ka [11]3 years ago
8 0

Answer: The correct answer is the weight of the wood.

Explanation:

Hope this helps

erica [24]3 years ago
7 0

Answer:

4 more people pls

Explanation:

mark me brainelest pls

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neonofarm [45]

A.224/96 Rn I think i'm right if i'm wrong i'm srry


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3 years ago
In right ΔPQR, sin P = 3 over 5 , and cos P = 4 over 5. What is tan P?
Dvinal [7]
Not sure if you learned S=O/H,C= A/H, T=O/A, but Sin is equal to opposite over hypotenuse, so draw a triangle, and label those angles (opposite= 3 and hypotenuse=5). Also, Cos is equal to adjacent over hypotenuse, so label those as well (you already have hypotenuse from Sin, and the Adjacent angle = 4). Therefore, Tan which equals opposite over adjacent is 3/4
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3 years ago
Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 2.20×106 N , one at an angle 15.0 ∘ west of north,
Darina [25.2K]

Answer:

The total work done by the two tugboats on the supertanker is 3.44 *10^9 J

Explanation:

The force by the tugboats acting on the supertanker is constant and the displacement of the supertanker is along a straight line.

The angle between the 2 forces and displacement is ∅ = 15°.

First we have to calculate the work done by the individual force and then we can calculate the total work.

The work done on a particle by a constant force F during a straight line displacement s is given by following formula:

W = F*s

W = F*s*cos∅

With ∅ = the angles between F and s

The magnitude of the force acting on the supertanker is F of tugboat1 = F of tugboat 2 = F = 2.2 * 10^6 N

The total work done can be calculated as followed:

Wtotal = Ftugboat1 s * cos ∅1 + Ftugboat2 s* cos ∅2

Wtotal = 2Fs*cos∅

Wtotal = 2*2.2*10^6 N * 0.81 *10³ m s *cos15°

Wtotal = 3.44*10^9 Nm = <u>3.44 *10^9 J</u>

<u />

The total work done by the two tugboats on the supertanker is 3.44 *10^9 J

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Answer:

nothing would happen

Explanation:

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