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3 years ago

What is the equation of a line that is perpendicular to this line and goes through the

Mathematics

1 answer:

-Dominant- [34]3 years ago

5 0

Answer:

x + 3y + 9 = 0

Step-by-step explanation:

y=3x + 2

Coefficient of x = 3

Gradient (m) of line y= 3x + 2 is 3

Since the line passing through point

(3,-4) is perpendicular to line y=3x + 2

hence gradient (m) of the line is -1/3;

And hence it equation is given as;

y - y1 = m(x - x1)

y - (-4) = -1/3(x - 3)

multiplying through by 3;

3 × y + 3 × 4 = 3 × -1/3(x - 3)

3y + 12 = -1(x - 3)

3y + 12 = -x + 3

x + 3y + 12 - 3 = 0

x + 3y + 9 = 0

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How would you solve this?

gulaghasi [49]

Answer:

Step-by-step explanation:

Find the slope = -2/1

Find the y-intercept = 5

Go to graph

put a dot at (0,5)

since it's a negative slope you will go up 2 and left 1

draw your line

_________________________________________________

Find the slope = 3/1

Find the y-intercept = 0

go to graph

Put a dot at (0,0)

Since it is a positive slope you will go down 3 and left 1.

To find the slope and y-intercept use this formula=

y=mx+b

m=slope

b=y-intercept

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3 years ago

The coordinate of M is 2.5 and MN = 4 what are the possible coordinates for N

stira [4]

The possible coordinates for N is 0

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3 years ago

Whats the gcf of 48 and 78

Liono4ka [1.6K]

The greatest common factor (GCF) of 48 and 78 is: 6

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Factors of 78: 1, 2, 3, 6, 13, 26, 39

The common factors between the two numbers are 1, 2, 3, and 6, but considering 6 is the highest number out of them, it is the greatest common factor.

5 0

3 years ago

Read 2 more answers

A sociologist develops a test to measure attitudes towards public transportation, and 27 randomly selected subjects are given th

taurus [48]

Answer:

The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 27 - 1 = 26

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0518