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iris [78.8K]
3 years ago
13

PLEASE I NEED YOUR HELP ​

Mathematics
2 answers:
gladu [14]3 years ago
5 0

Answer:

-(7/9)

Step-by-step explanation:

Tcecarenko [31]3 years ago
4 0

Answer:

<h2>D) - 9/7</h2>

Hope this will help you lot.

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Find a fraction equivalent to 5/7 whose squared terms add up to 1184.
bogdanovich [222]

The system of equations of two unknowns is formulated and solved.

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y  } \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}

                                                              \large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \  \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28  } \end{gathered}$}

                                                                  \large\displaystyle\text{$\begin{gathered}\sf \bf{ x=\dfrac{5}{7}(\pm 28)=\pm 20  } \end{gathered}$}

The fraction that satisfies the request is \bf{\dfrac{20}{28}} , since in \bf{\dfrac{-20}{-28}} the negative signs are canceled and the first fraction is obtained.

3 0
2 years ago
-2x+5=4x-7 solve for x. Show all work
Neko [114]

Answer:

2=x

Step-by-step explanation:

-2x+5=4x-7

+2x     +2x

5=6x-7

+7     +7

12=6x

/6

2=x

7 0
3 years ago
Read 2 more answers
Erin found 9 cents<br> each day for 7 days.<br> How much money did<br> she find in all?
kherson [118]
After 7 days she would have eventually found 63 cents.
8 0
3 years ago
Read 2 more answers
Given f(x) = 2x + 5 and g(x) = 3x + 6
Kryger [21]
I hope this helps you



f(8)=2.8+5=21


g(8)=3.8+6=30


f-g(8)=21-30= -9
6 0
3 years ago
Read 2 more answers
p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.
Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

\frac{p}{q {r}^{2} }  = k

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

\frac{200}{2(3) {}^{2} }  = k

\frac{200}{18}  = k

\frac{100}{9}  = k

Now, since we know our constant, let find p.

\frac{p}{q {r}^{2} }  =  \frac{100}{9}

Q is 5, and r is 2.

\frac{p}{5( {2}^{2}) }  =  \frac{100}{9}

\frac{p}{20}  =  \frac{100}{9}

p =  \frac{2000}{9}

3 0
2 years ago
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