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3 years ago

Explain why the exponents cannot be added in the product 12^3 x 11^3

2 answers:

7 0

The exponent cannot be added to the product because it stated in the law of exponents. An exponent is simply the shorthand in multiplying your base number. Exponent will give how many times you will multiply the base numbers. It is not possible that you add both exponents in the given situation because they have different value together.
=> 12^3 x 11^3
If we solve this equation following the rule of exponent will get the correct answer:
=> (12 x 12 x 12) x (11 x 11 x 11)
=> 1728 X 1331
=> the answer is 2 299 968
But if we add the exponent, the answer would be wrong
=> 12^3 x 11^3
=> 132^6
=> 5289852801024 which is wrong.

Mrac [35]3 years ago

5 0

List three ways to express 3 as a product of power

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Graph the quadratic function f(x) = -2x^2 + 5x + 2

larisa86 [58]

Answer:

Step-by-step explanation:

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3 years ago

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Factor the expression 4r^2 - 64

Shkiper50 [21]

Answer:

4(r+4)(r-4)

Step-by-step explanation:

If you factor it out, then it will be 4(r+4)(r-4). You can double check by multiplying it.

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3 years ago

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4. Gloria the grasshopper is working on her hops.

aivan3 [116]

The path that Gloria follows when she jumped is a path of parabola.

The equation of the parabola that describes the path of her jump is $\mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}$

The given parameters are:

$\mathbf{Height = 20}$

$\mathbf{Length = 28}$

<em>Assume she starts from the origin (0,0)</em>

The midpoint would be:

$\mathbf{Mid = \frac 12 \times Length}$

$\mathbf{Mid = \frac 12 \times 28}$

$\mathbf{Mid = 14}$

So, the vertex of the parabola is:

$\mathbf{Vertex = (Mid,Height)}$

Express properly as:

$\mathbf{(h,k) = (14,20)}$

A point on the graph would be:

$\mathbf{(x,y) = (28,0)}$

The equation of a parabola is calculated using:

$\mathbf{y = a(x - h)^2 + k}$

Substitute $\mathbf{(h,k) = (14,20)}$ in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{y = a(x - 14)^2 + 20}$

Substitute $\mathbf{(x,y) = (28,0)}$ in $\mathbf{y = a(x - 14)^2 + 20}$

$\mathbf{0 = a(28 - 14)^2 + 20}$

$\mathbf{0 = a(14)^2 + 20}$

Collect like terms

$\mathbf{a(14)^2 =- 20}$

Solve for a

$\mathbf{a =- \frac{20}{14^2}}$

$\mathbf{a =- \frac{20}{196}}$

Simplify

$\mathbf{a =- \frac{5}{49}}$

Substitute $\mathbf{a =- \frac{5}{49}}$ in $\mathbf{y = a(x - 14)^2 + 20}$

$\mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}$

Hence, the equation of the parabola that describes the path of her jump is $\mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}$

See attachment for the graph

Read more about equations of parabola at:

brainly.com/question/4074088

7 0

2 years ago

Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Andrei [34K]

Answer:

Circle 1=6x+2y

Rectangle 4 = 3x+y

Circle 4 = 5x

Step-by-step explanation:

4x+3y and 2x-y can be added to find result for the circle.

Let C1 represent circle 1

4x+3y+2x-y=C1\\

Combining\:like\:terms\\

4x+2x+3y-y=C1

6x+2y=C1

So, The result is: C1=6x+2y

Now, We need to solve:

Let R1 represent rectangle 4

x+4y + R1 = 4x+5y

R1=4x+5y-(x+4y)

R1=4x+5y-x-4y

R1=4x-x+5y-4y

R1=3x+y

So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y

Now, We need to solve the equation:

Let C4= Circle 4

2x-y+3x+y=C4

Combining the like terms

2x+3x-y+y=C4

5x=C4

So, Solving 2x-y+3x+y=C4 we get C4 = 5x

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3 years ago

Jeff left 4/5 of the pumpkin pie in the refrigerator on Saturday he ate 1/2 if what was left of the pie what fraction of the ent

sukhopar [10]

He ate 2/5 of the pie on Saturday.

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3 years ago