Question

Jane left the school and started to bike along the road at a rate of 12 mph. Her friend Sally left the school 10 minutes after Jane, biking on the same road at a rate of 15 mph. How long will it take Sally to catch up with Jane?

Answer 1

Answer: Sally will catch up with Jane after 50 minutes.

Step-by-step explanation:

Since we have given that

Speed of Jane of biking = 12 mph

After 10 minutes,

Speed of Sally of biking = 15 mph

Let the distance be 'x'.

According to question, our required equation becomes,

$\dfrac{x}{12}-\dfrac{x}{15}=\dfrac{10}{60}\\\\\dfrac{5x-4x}{60}=\dfrac{1}{6}\\\\\dfrac{1x}{60}=\dfrac{1}{6}\\\\x=10\ miles$

Thus, total distance would be 10 miles.

So, the time taken by Sally to catch up with Jane is given by

$\dfrac{10}{12}=\dfrac{5}{6}\times 60=50\ minutes$

Hence, Sally will catch up with Jane after 50 minutes.

Answer 2

Answer:

10/3 hours

Step-by-step explanation:

12x=15x-10

12x-15x=15x-10-15x

-3x=-10

-3x/-3=-10/-3

x=10/3