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Vera_Pavlovna [14]
3 years ago
8

What is the common difference for this arithmetic sequence?

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
6 0

Answer: +17

Step-by-step explanation: The common difference is the number that your repeatedly adding or subtracting to reach the next term.

Here, notice that your adding 17 to get from 31 to 48.

In the same way, your adding 17 to get from 48 to 65.

Your also also adding 17 to get from 65 to 82.

Since you keep on adding 17, the common difference is +17.

MaRussiya [10]3 years ago
4 0

Common difference of the arithmetic sequence, is

d=a_{n} - a_{n-1}

d = a_{2} -a_{1} = 48-31=17 \\ \\d= a_{3} -a_{2} = 65 - 48= 17 \\ \\ d= a_{4} -a_{3}= 82-65=17 \\ \\ Answer:\ D.17.

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Nimfa-mama [501]

Answer:

a = 5

Step-by-step explanation:

a +a+4 + 2a-3 = 21

4a +1 =21

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3 years ago
Help me................​
Taya2010 [7]

Answer:

x = 5. y = 4

Step-by-step explanation:

7x - 4 = 31

7x = 35

x = 5

4y + 8 = 24

4y = 16

y = 4

4 0
3 years ago
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What is the LCM of 15 and 25
Tresset [83]

Hello there!

Factors of 15: 1, 3, 5, 15

Factors of 25, 1, 5, 25

5*5*3=75

The least common factor of 15 and 25 is 75 is the right answer.

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

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3 years ago
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Triangle ABC is congruent to triangle DEF. If DE = 41, EF = 23, DF = 36, and AB = 8x − 7, what is x? Round to the nearest tenth.
Nadya [2.5K]

The side AB is equal to the side DE. Then the value of x is 6.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

Triangle ABC is congruent to triangle DEF.

If DE = 41, EF = 23, DF = 36, and AB = 8x − 7.

Then the side AB is equal to the side DE.

    AB = DE

8x - 7 = 41

    8x = 48

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Then the value of x is 6.

More about the triangle link is given below.

brainly.com/question/25813512

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2 years ago
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T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
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