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Vera_Pavlovna [14]
4 years ago
8

What is the common difference for this arithmetic sequence?

Mathematics
2 answers:
xxTIMURxx [149]4 years ago
6 0

Answer: +17

Step-by-step explanation: The common difference is the number that your repeatedly adding or subtracting to reach the next term.

Here, notice that your adding 17 to get from 31 to 48.

In the same way, your adding 17 to get from 48 to 65.

Your also also adding 17 to get from 65 to 82.

Since you keep on adding 17, the common difference is +17.

MaRussiya [10]4 years ago
4 0

Common difference of the arithmetic sequence, is

d=a_{n} - a_{n-1}

d = a_{2} -a_{1} = 48-31=17 \\ \\d= a_{3} -a_{2} = 65 - 48= 17 \\ \\ d= a_{4} -a_{3}= 82-65=17 \\ \\ Answer:\ D.17.

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Answer the question and answer it down below
Sergio039 [100]

Answer:

4:24 p.m.

Step-by-step explanation:

Figure out how often the buses leave at the same time. This is the same as the least common multiple (LCM) of how often they leave the stadium.

The LCM is found by multiplying the maximum number of each prime factor found in any of the numbers.

The prime factors of a number are found by dividing it by whole numbers until the factors are all prime. Prime numbers only have the factors 1 and itself.

6 = 2 X 3

8 = 2 X 2 X 2

The greatest times 2 repeats is three times.

The greatest times 3 repeats is one time.

2 X 2 X 2 X 3 = 24

The LCM is 24, and the buses have the same leaving times every 24 minutes.

Find 24 minutes after 4:00 p.m. Change the minutes only, which are the numbers right of the colon : .

The buses will next leave together at 4:24 p.m.

5 0
3 years ago
Which partial quotients could be added to find 396 ÷ 12?
Travka [436]

Answer:

33 plz braniest i think i help you

Step-by-step explanation:

3 0
3 years ago
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A football team won 16 games last year. This year the team won 20 games. What is the percent increase in the number of games the
lana66690 [7]

Answer:

25%

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4 0
3 years ago
Max w = 5y1 + 3y2<br> s. a.<br> y1 + y2 ≤ 50<br> 2y1 + 3y2 ≤ 60<br> y1<br> , y2 ≥ 0
CaHeK987 [17]

The maximum value of the objective function is 330

<h3>How to maximize the objective function?</h3>

The given parameters are:

Max w = 5y₁ + 3y₂

Subject to

y₁ + y₂ ≤ 50

2y₁ + 3y₂ ≤ 60

y₁ , y₂ ≥ 0

Start by plotting the graph of the constraints (see attachment)

From the attached graph, we have:

(y₁ , y₂) = (90, -40)

Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂

w = 5 * 90 - 3 * 40

Evaluate

w = 330

Hence, the maximum value of the function is 330

Read more about objective functions at:

brainly.com/question/26036780

#SPJ1

7 0
2 years ago
Answer please!!!!!!!!!!!!!!!!!!
castortr0y [4]
The rule is "whatever the input is, multiply it by 5, then subtract 2"

For example, if the input is 4 then 4*5 = 20 and 20-2 = 18
So in short, the input 4 leads to the output 18 as shown in the top row of the diagram. 

The answer is the box on the bottom row, right hand side where it says "x 5"  and "-2" in the two bubbles.
7 0
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