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2 years ago

PLEASE HURRY ITS TIMED!!!

Mathematics

1 answer:

irina1246 [14]2 years ago

5 0

Answer:

The correct answer is A)

PRISM.

Explanation:

Any 2-dimensional shape formed with straight lines is a polygon. Examples of polygons are:

Quadrilaterals
Hexagons
Pentagons, and
Triangles are all examples of polygons. The name of polygons are usually indicative of the number of sides they have.

Cheers!

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1/5 (4-3x) = 1/7 (3x - 4) pls solve it pls pls

8_murik_8 [283]

Answer:

x=4/3

Step-by-step explanation:

In pic

(hope this helps can I pls have brainlist (crown)☺️)

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2 years ago

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Lexie rolls a six-sided number cube 1200 times.

Bingel [31]

Answer:

your answer is D lexie will roll an even number roughly 400 times but not exactly 400 times

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3 years ago

Evaluate the following expression. y + 9 when y = 12

tino4ka555 [31]

Answer:

Step-by-step explanation:

y+9 = ?

y=12

12+9=21

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2 years ago

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. One of the x-interc

Marina CMI [18]

3x^2 + 6x - 10 = 0
3(x^2 + 2x) - 10 = 0
3[ (x + 1)^2 - 1 ] - 10 = 0
3(x+1)^2 - 13 = 0

so the vertex is at (-1,-13)
the roots will be same distance from x = -1
that is a distance 1.08 --1 = 2.08

so other root is approximately -1 -2.08 = -3.08

the other intercept is at (-3.08,0)

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3 years ago

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Can someone please help me with my Question #29 of The Quadratic Relations for me please?

lara [203]

Answer:

Calculate the first differences between the y-values:

$\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19$

As the first differences are not the same, we need to calculate the second differences:

$\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7$

As the second differences are the same, the relationship between the variable is quadratic and will contain an $x^2$ term.

--------------------------------------------------------------------------------------------------

To determine the quadratic equation

The coefficient of $x^2$ is always half of the second difference.

As the second difference is 2, and half of 2 is 1, the coefficient of $x^2$ is 1.

The standard form of a quadratic equation is: $y=ax^2+bx+c$

(where a, b and c are constants to be found).

We have already determined that the coefficient of $x^2$ is 1.

Therefore, a = 1

From the given table, when $x=0$ , $y=12$ .

$\implies a(0)^2+b(0)+c=12$

$\implies c=12$

Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:

$\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}$

Therefore, the quadratic equation for the given ordered pairs is:

$y=x^2+6x+12$

7 0

1 year ago