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natali 33 [55]
3 years ago
15

A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body di

agram shows the forces acting on the cart.
The mass of the cart, to the nearest whole number, is kg?

Chemistry
2 answers:
RideAnS [48]3 years ago
6 0
The answer is 146 kg. 
AleksAgata [21]3 years ago
3 0

Answer : The mass of the cart is, 146 Kg.

Solution : Given,

Force = 250 N

Angle = 35^o

Acceleration = 1.4m/s^2

Formula used :

F\times \cos \theta=m\times a

where,

F = force

\theta = angle

a = acceleration

m = mass of the cart

Now put all the values in the above formula, we get the mass of the cart.

250N\times \cos (35^o)=m\times (1.4m/s^2)

m=146Kg

Therefore, the mass of the cart is, 146 Kg.

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Glucose (C6H12O6)(C6H12O6) can be fermented to yield ethanol (CH3CH2OH)(CH3CH2OH) and carbon dioxide (CO2).
zhenek [66]

Answer: a) 49.8 gram

b) 47.0 %

Explanation:

First we have to calculate the moles of glucose

\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles

The balanced chemical reaction will be,

C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2

From the balanced reaction, we conclude that

As,1 mole of glucose produce = 2 moles of ethanol

So, 0.54 moles of glucose will produce =  \frac{2}{1}\times 0.54=1.08 mole of ethanol

Now we have to calculate the mass of ethanol produced

\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}

\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g

Now we have to calculate the percent yield of ethanol

\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%

Therefore, the percent yield is 47.0 %

7 0
3 years ago
Identify the combustion reaction
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The combustion reaction is the last one, with the C4H12 compound.

Remember that all the combustion reactions has the oxygen as a substract and for products, you'll have CO2 and water.

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Which of the following solutions is more concentrated?<br> 0.50M KCl or 5.0% (w/v) KCl
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.50 M KCl because 5% is the same as .05, which makes the .50M more concentrated.

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synthesize the following compound from benzene. use a diazonium salt as one of the synthetic intermediates.
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Reacting nitrous acid with aromatic amines to produce diazonium salt is one of the most used processes. An aromatic amine called aniline reacts with nitrous acid to generate benzene diazonium chloride, a diazonium salt.

To create azo colors, benzene diazonium chloride combines with phenol, -napthol, aniline, and 2-methylaniline. These reactions result in the removal of an HCl molecule. Red organic dye is created when benzene and benzene diazonium chloride interact. Since the solutions created in this method do not last, the reactions involving a diazonium salt are always carried out with a freshly prepared solution. Diazonium salts are very flammable when they are solid because of their instability.

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7 0
1 year ago
Calculate the Molecular or Formula massof each of the following:
DiKsa [7]

Explanation:

Molar mass  

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

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Phosphorous , P = 31 g/mol

Molecular mass of  P₄ = ( 4 * 31 ) = 124 g/mol .

(b) H₂O

Molar mass of of the atoms are -

Hydrogen , H = 1 g/mol

oxygen , O = 16 g/mol.

Molecular mass of H₂O = ( 2 * 1 ) + ( 1 * 16 ) = 18 g/mol

(c) Ca(NO₃)₂

Molar mass of of the atoms are -

calcium , Ca = 40 g/mol

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oxygen , O = 16 g/mol.

Molecular mass of  Ca(NO₃)₂ = ( 1 * 40 ) + ( 2 * 14 ) + ( 6 * 16 ) = 164 g/mol.

(d)CH₃CO₂H (acetic acid)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol.

oxygen , O = 16 g/mol.  

Hydrogen , H = 1 g/mol

Molecular mass of CH₃CO₂H =( 2 * 12 ) + (2 * 16 ) + (4 * 1 ) = 60 g/mol.

(e) C₁₂H₂₂O₁₁ (sucrose, cane sugar).

Molar mass of of the atoms are -

Carbon , C = 12 g/mol.

oxygen , O = 16 g/mol.  

Hydrogen , H = 1 g/mol

Molecular mass of C₁₂H₂₂O₁₁ = (12 * 12 ) + ( 22 * 1 ) + ( 11 * 16 ) = 342 g/mol.

 

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3 years ago
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