Identify the salt that is produced from the acid-base neutralization reaction between potassium hydroxide and acetic acid.

The hybridization associated with the central atom of a molecule in which all the bond angles are 180° is ____.

enot [183]

Answer:

Sp hybrid

Explanation:

Sp is linear I n shape

7 0

3 years ago

What stage in the cell cycle does the DNA duplicate?

Marizza181 [45]

Answer: 1. Interphase

3 0

2 years ago

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During respiration, energy is retrieved from the high-energy bonds found in certain organic molecules. Which of the following, i

babunello [35]

Answer:

(A.) CO2, H2O

Explanation:

The chemical equation for respiration process is:

$C_{6}H_{12} O_{6}$ + $6O_{2}$ → $6CO_{2}$ + $6H_{2} O$ + ATP↑

Energy is released during the biochemical process in the organism's cells in form of ATP. Byproducts of the reaction are carbon dioxide and water molecules.

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4 0

2 years ago

Which member of the following pairs has the larger London dispersion forces?

Virty [35]

Answer:

H₂S; CO₂; SiH₄

Explanation:

London dispersion forces are larger in molecules that are large and have more atoms or electrons.

A. H₂O or H₂S

H₂S. S is below O in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

B. CO₂ or CO

CO₂. CO₂ has more atoms. It is also linear, so the molecules can get close to each other and maximize the attractive forces.

C. CH₄ or SiH₄

CH₄. Si is below C in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

4 0

3 years ago

What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?

mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

$C=\frac{n}{V}$ .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is $K_{2}SO_{4}$ thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass

Putting the values,

$n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol$

Thus, number of moles of $K_{2}SO_{4}$ will be $0.1061\times 0.5=0.053 mol$ .

The volume of solution is 225 mL, converting this into L,

$1 mL=10^{-3}L$

Thus,

$225 mL=0.225 L$

Putting the values in equation (1),

$C=\frac{(0.053 mol}{0.225 L}=0.236 M$

Therefore, concentration of potassium sulfate solution is 0.236 M.

4 0

3 years ago