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2 years ago

if the side of a square is tripled,how many times the perimeter of the first square will that of the new square be?

Mathematics

2 answers:

evablogger [386]2 years ago

7 0

Answer:

yesyesyesyesyesyes good job baby hahahahhaha

Sergio [31]2 years ago

6 0

Answer:

The perimeter of the new square is three times the perimeter of the first one.

Step-by-step explanation:

You just need to put in an example number to figure this out.

Lets say one square has a side of two, and another a side of 6.

Perimeter of square 1: 8

Perimeter of square 2: 24

24 is three times more than 8.

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Help asappppp tyyy

True [87]

Given:

Compound shape

To find:

The area of the compound shape.

Solution:

The compound shape is splitted into two parallelograms.

<u>Bottom parallelogram:</u>

Base = 7.5 cm

Height = 5 cm

Area of the parallelogram = base × height

= 7.5 × 5

= 37.5 cm²

The area of the Bottom parallelogram 37.5 cm².

<u>Top parallelogram:</u>

Base = 7.5 cm

Height = 4.5 cm

Area of the parallelogram = base × height

= 7.5 × 4.5

= 33.75 cm²

The area of the top parallelogram 33.75 cm².

Compound shape = 37.5 + 33.75

= 71.25 cm²

The area of the compound shape is 71.25 cm².

7 0

2 years ago

The two equations will intersect at which of the following coordinates : y= -x + 3 y= 1/2x

kvv77 [185]

Y=1/2 the points would intersect

4 0

2 years ago

Enter the sum of numbers as a product of their GCF.

frutty [35]

Their GCF is 6 and the sum is 66

Step-by-step explanation:

8 0

2 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

2 years ago

What is the gravity of a location if the mass of an object is 300 kg and it has a weight of 450N ?

kozerog [31]

The gravity is 1.5m\s^2

Further explanation:

The weight of any object is given by the product of mass and gravity of the object

Let

m denote the mass of object

g be the gravity

and

w be the weight

Then the statement can be mathematically written as:

$w=m*g$

Given

m=300kg

w=450N

Putting the values of m and w into the formula

$450=g*300\\g= \frac{450}{300}\\g=1.5\ ms^{-2}$

The gravity is 1.5m\s^2

Keywords: Mass, Gravity

Learn more about gravity at:

#LearnwithBrainly

7 0

2 years ago