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Vikki [24]
3 years ago
10

The weather report says the temperature is 20°C and will drop 5°C per hour for the next 6 hours. Daryl plans to be gone for at l

east 6 hours, and he has a plant outside. If he wants the plant to remain in temperatures above –10°C, should Daryl move his plant to a warmer location before leaving? An inequality to model the problem is . The solution is
Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

Step-by-step explanation:

i really dont quite understand  the question can u send a pic or anything to fully understand

allochka39001 [22]3 years ago
4 0

Answer:

The weather report says the temperature is 20°C and will drop 5°C per hour for the next 6 hours. Daryl plans to be gone for at least 6 hours, and he has a plant outside. If he wants the plant to remain in temperatures above –10°C, should Daryl move his plant to a warmer location before leaving?

An inequality to model the problem is  

✔ 20 - 5x > -10

.

The solution is  

✔ x < 6

.

Step-by-step explanation: nobody could answer it correctly so here.

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Answer:

Original price reduced by 30%

Step-by-step explanation:

You want the deepest discount, which means you want the greatest percent/amount off. The first choice is 20%. The second is 30%. The third one is 25%, because you are paying for 75% (100-75). The second choice offers the deepest discount because it is 30% off.

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13. The initial value of a particular vehicle is $20,000. After one year, the vehicle is worth $17,000. If the
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A fraction becomes 4÷5 if 1 is added to both numerator and denominator. If, however, 5 is subtracted from both numerator and den
tia_tia [17]

Answer:

\dfrac{7}{9}

Step-by-step explanation:

\dfrac{x+1}{y+1}=\dfrac{4}{5}\\\Rightarrow 5x-4y=-1

\dfrac{x-5}{y-5}=\dfrac{1}{2}\\\Rightarrow 2x-y=5

Putting it in matrix form

\begin{bmatrix}a_{1}&b_{1}\\a_{2}&b_{2}\end{bmatrix}{\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}{c_{1}}\\{c_{2}}\end{bmatrix}\\\Rightarrow\begin{bmatrix}5 & -4\\2 & -1\end{bmatrix}\begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}-1\\ 5\end{bmatrix}

From Cramer's rule we have

x=\dfrac{\begin{vmatrix}c_1 &b_1 \\ c_2 & b_2\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow x=\dfrac{\begin{vmatrix}-1 &-4 \\ 5 & -1\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1\end{vmatrix}}\\\Rightarrow x=\dfrac{1+20}{-5+8}\\\Rightarrow x=7

y=\dfrac{\begin{vmatrix}a_1 &c_1 \\ a_2 & c_1\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow y=\dfrac{\begin{vmatrix}5 &-1 \\ 2 & 5\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1 \end{vmatrix}}\\\Rightarrow y=\dfrac{25+2}{-5+8}\\\Rightarrow y=9

Verifying the results

\dfrac{7+1}{9+1}=\dfrac{8}{10}=\dfrac{4}{5}

\dfrac{7-5}{9-5}=\dfrac{2}{4}=\dfrac{1}{2}

Hence, the fraction is \dfrac{7}{9}.

6 0
3 years ago
F(x) = square root 2x
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\\ \sf\longmapsto (f.g)(x)

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\\ \sf\longmapsto \sqrt{100x^2}

\\ \sf\longmapsto 10x

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2 years ago
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