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vesna_86 [32]
2 years ago
15

Answer the problem :)

Mathematics
1 answer:
Tomtit [17]2 years ago
5 0
The domain is the value of x. In this case, -3≤x≤7
the range is the value of y. in this case, -1≤y≤9

this is not a function, because the same x value has two corresponding y values. For example, when x=5, y=0 or y=8

It IS a function if every x value has only one corresponding y value. 
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Greatest common factor of 66 and 77, will mark brainlist to the first 1 who gets it right
fiasKO [112]

Answer:

D (11)

Step-by-step explanation:

77 / 11 = 7

66/11 = 6

5 0
3 years ago
Read 2 more answers
If someone could help me that would be amazing! Thank you!
Anastasy [175]
I’d say 135 or B! I hope this helps!
4 0
3 years ago
Approximately how much more quickly (in mph) does a pilot traveling 400 mph and rising at an angle of 30o gain altitude versus a
REY [17]
We can find the height of the altitude by the ratio of sin. See my attachment.
sin of angle = side in front of the angle / hypotenuse
sin x = height/distance

If the two pilot is rising in an hour, then the first distance is 400 miles, the second distance is 300 miles.

Find the height of first pilot
height/distance = sin x 
height/400 = sin 30°
height = sin 30° × 400
height = 1/2 × 400
height = 200

Find the height of second pilot
height/distance = sin x 
height/300 = sin 40°
height = sin 40° × 300
height = 0.642 × 300
height = 192

So the first pilot traveling 400 mph with 30° is more quickly to reach high altitude than the second pilot traveling 300 mph with 40°

3 0
3 years ago
Pls help i am on a timer
stich3 [128]

Answer:

x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Step-by-step explanation:

Given;

x² - 2x - 1 = 0

Solve by completing the square method;

⇒ take the constant to the right hand side of the equation.

x² - 2x = 1

⇒ take half of coefficient of x = ¹/₂ x -2 = -1

⇒ square half of coefficient of x and add it to the both sides of the equation

x^2 +  (-1)^2 = 1 + (-1)^2

(x-1)^2 = 1 + 1\\\\(x-1)^2 = 2\\\\

⇒ take the square root of both sides;

x-1 = +/- \ \ \sqrt{2} \\\\x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Therefore, option B is the right solution.

3 0
2 years ago
Someone please help me
lutik1710 [3]

Answer:

18

Step-by-step explanation:

I did that in my head could be wrong

3 0
3 years ago
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