Please help me out!!!!!

In 1984 a locally-owned car company sold 2,743 cars. In 2003, the car sales rose to 4,069. What was the average rate of change f

tatiyna

Answer:

70 cars per year.

Step-by-step explanation:

Given:

In 1984 a locally-owned car company sold 2,743 cars.

In 2003, the car sales rose to 4,069.

Question asked:

What was the average rate of change for the total number of cars sold?

Solution:

In 2003 number of cars sold = 4069

In 1984 number of cars sold = 2743

Change in the number of car sold = 4069 - 2743

= 1326

Now, time interval between 2003 and 1984 = 19

$The\ average\ rate\ of\ change=\frac{Change\ in\ the\ number\ of\ car\ sold}{Time \ interval}$

$=\frac{1326}{19} \\=69.789\\\\=70\ cars\ per\ year\ (approx)$

Thus, the average rate of change for the total number of cars sold is 70 cars per year.

7 0

3 years ago

recipe for brownies calls for 34 cup of sugar. Skylar has a bag that contains 912 cups of sugar. Exactly how many batches of bro

Effectus [21]

To answer this question, you need to divide the amount of sugar you have, 912 cups, by the amount needed for a batch, 34. The answer is 26.82353 (rounded). When this is changed to a mixed number, the answer is 26 14/17

7 0

3 years ago

A software engineer is creating a new computer software program. She wants to make sure that the crash rate is extremely low so

Soloha48 [4]

Answer:

a) the sample size is 400

b) 95% confidence Interval for p is ( 0.0286, 0.0714 )

Step-by-step explanation:

Given the data in the question;

sample size n = 400

x = 20

p = x / n = 20 / 400 = 0.05

q = 1 - p = 1 - 0.05 = 0.95

a)

n = 400

Hence, the sample size is 400

b) 95% confidence Interval for p;

At 95% confidence interval,

significance level ∝ = 1 - 95% = 1 - 0.95 = 0.05

∝/2 = 0.05 / 2 = 0.025

so, Z critical Value ; $Z_{\alpha /2$ = 1.96 { from table }

So for Confidence Interval for p;

⇒ p' ± $Z_{\alpha /2$ √( p'q' / n )

we substitute

⇒ 0.05 ± 1.96√( (0.05 × 0.95 ) / 400 )

⇒ 0.05 ± 1.96√( 0.00011875 )

⇒ 0.05 ± 1.96 × 0.010897

⇒ 0.05 ± 0.021358

⇒ ( 0.05 - 0.021358 ), ( 0.05 + 0.021358 )

⇒ ( 0.0286, 0.0714 )

Therefore, 95% confidence Interval for p is ( 0.0286, 0.0714 )

8 0

3 years ago

Adam plans to choose a video game from a section of the store where everything is 75% off. He writes the expression −0.75 to fin

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

Adam plans to choose a video game from a section of the store where everything is 75% off.

The expression written by him for this situation is d - 0.75d.

Here, the part d represents the sale price before discount and the part 0.75d is the discount amount.

The expression written by Rena is 0.25d.

Here, the part 0.25d is the price after discount. Since 75% is the discount, the rate after disount is 25% and 25% of d is 0.25d.

6 0

3 years ago

For quadrilateral ABCD, determine the most precise name for it. A(-2,3), B(9,3), C(5,6) and D(2,6). Show your work and explain.

horsena [70]

To solve this problem you must apply the proccedure shown below:

1. You have the following points given in the problem above:

A<span>(-2,3), B(9,3), C(5,6) and D(2,6)

2. When you plot them, you obtain the figure shown in the graph attached.

3. Therefore, as you can see, the answer is: the figure is a trapezoid, which is define as a quadrilateral with two parallel sides.</span>

8 0

3 years ago