If the data for the heights of players on a basketball team is skewed right, which statistical measure represents the spread of
2 answers:
You might be interested in
Answer:
108
Step-by-step explanation:
View Image.
Whenever you have a limit and the answer to that limit is one of the indeterminant form, you can use the L'Hopital's Rule to solve for the limit.
<u>Indeterminant forms:</u>
<u>L'Hopitals Rule:</u>
L'Hopitals rule is just taking the derivative of the numerator, and the derivative of the denominator separately.
After doing the L'Hopital's rule, take the limit again. If the result is an actual number then you got your answer.
If the result is another indeterminant form then use L'Hopitals rule again and check the limit again after that. Repeat the process until you get your answer.
Answer:
R = 7,34 km
Ф = 63,43° north of east
Step-by-step explanation:
Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.
To determine the perpendicular components, we will use right triangles trigonometrics ratios.
Please see images for each displacement in attached file.
- <u>Displacement A: 2.50 km and 45° north of west</u>
Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)
Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)
- <u>Displacement B: 4.70 km and 60° south of east</u>
Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)
By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)
- <u>Displacement C: 1.30 km and 25° south of west </u>
Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)
Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)
- <u>Displacement D: 5.10 km due east (0°)</u>
Dx= DcosФ = 5.10 km (pos. direction)
Dy= DsenФ = 0 km
- <u>Displacement E: 1.70 km and 5° east of north</u>
Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)
Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)
- <u>Displacement F: 7.20 km and 55° south of west</u>
Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)
Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)
- Displacement G: 2.80 km and 10° north of east
Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)
Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)
Now, we add the components along the x- and y- axis to find the components of the resultant (R):
Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx
Ry = Ay + By + Cy + Dy + Ey + Fy + Gy
Therefore,
Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)
Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)
<em>Note: minus (-) symbol to negative directions</em>
Rx = 3.28 km
Ry = - 6.57 km
Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:
R = 7,34 km
To find the direction of the resultant:
tanФ =
tanФ =
tanФ = 2.00
Ф = tan-1 (2.00)
Ф = 63,43° north of east