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Nikitich [7]
2 years ago
5

If the data for the heights of players on a basketball team is skewed right, which statistical measure represents the spread of

the data best?
A. Interquartile Range
B. Mean
C. Median
D. Range
Mathematics
2 answers:
finlep [7]2 years ago
5 0
Answer: C median use process eliminating
mestny [16]2 years ago
3 0

Answer:

Median

Step-by-step explanation:

I know that you can't do Range, since it's skewed right.

The mean can't be it since it's also not representative when it's skewed right.

I'd say Median, or IQR at first glance but if you look at a graph, the IQR might follow with the skewed and move over a bit.

That leaves Median.

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The measure of the​ angle's supplement is 60
Sever21 [200]

Answer:

80°

Step-by-step explanation:

Let the angle be x then four times it's complement plus 60, that is

4(90 - x) + 60 ← is it's supplement

Supplementary angles sum to 180°

Sum the angle and it's supplement and equate to 180

x + 4(90 - x) + 60 = 180 ← distribute and simplify left side

x + 360 - 4x + 60 = 180

- 3x + 420 = 180 ( subtract 420 from both sides )

- 3x = - 240 ( divide both sides by - 3 )

x = 80

The required angle = x = 80°

supplement = 4(90 - 80) + 60 = 4 × 10 + 60 = 40 + 60 = 100°

4 0
2 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
Read 2 more answers
For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = \sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }

3 0
2 years ago
Suppose the z value for a number is –1.50. this means the number is
slega [8]
... 1.5 standard deviations below the mean.
3 0
3 years ago
Giving brainliest !! *easy*
Zepler [3.9K]

Answer: 49

Step-by-step explanation:

The missing constant term in the perfect square is 49.

x^2 + 14x + 49

We need a squart root of something to make the factor add up equal to 14x. If it's a perfect square, we could divide 14 by 2, 14/2 = 7, and we multiply 7^2, we get 49, which is a perfect square.

4 0
2 years ago
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