Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Answer:
The upper quartile is 6.
Step-by-step explanation:
FIrst, I found the median of the data, which is 4. Then, I determined the median of the upper half of the data, which is 6. The median of the upper half of the data is known as the upper quartile.
Answer:
4
Step-by-step explanation:
The function is given as 5c+cd, c=1/5 and d=15d.
We evaluate by substituting the given values of c and d in the function:
After substituting, we find the function's equivalent as 4.
Hence, the value of the function is 4
Answer:
Here it is
Step-by-step explanation:
#1. 3:4
#2. 3 to 4
#3. 3/4
Percent means parts out of 100
x%=x/100
4.25%=4.25/100=425/10000=85/2000=17/400
answer is 17/400
