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elena-s [515]
3 years ago
5

Write two different sentences that use ratios to describe the number of eyes and legs to this picture.

Mathematics
1 answer:
konstantin123 [22]3 years ago
3 0

Answer:

8 legs 4 eyes

Step-by-step explanation:

A hippo and a turtle

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Answer: I believe you may be right although I can't really explain it in detail

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Simplify the expression to a polynomial in standard form. (X+1)(3x^2+9x+2)
OLEGan [10]

Answer:

3x^3 + 12x^2 +11x +2

Step-by-step explanation:

this is also a cube root expanded If that helps

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What is the slope of the line on the graph need answer ASAP please thank you I'm in k-12​
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Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0<×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
What is the solution to the system of equations 2x-y=7 and y=2x+3
Yuri [45]
Make y the subject in both equations

2x-y=7

-y=-2x+7

y=2x-7

For the second equation

y=2x+3

The two equations are parallel because they have the same gradient or slope but different y intercepts.

This type of equations have no solution because they will never intersect.

NO SOLUTION

The correct answer is C
6 0
2 years ago
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