Question

1. Let f(x) be defined by the linear function graphed below and

Answer 1

Answer:

Step-by-step explanation:

A). g(x) = x² - 9x + 14

     Since coefficient of highest degree term (x²) is positive, parabola will open upwards.

    For any parabola opening upwards,

    Right end behavior,

    y → ∞ as x → ∞

B). Let the equation of the linear function is,

    f(x) = mx + b

    Where m = slope of the function

    b = y-intercept

    From the graph attached,

    Slope 'm' = $\frac{\text{Rise}}{\text{Run}}=\frac{-(2+1)}{(0+1)}$

    m = -3

    b = -1

    Therefore, function 'f' will be,

    f(x) = (-3)x - 1

    f(x) = -3x - 1    

    g(x) = x² - 9x + 14

           = x² - 7x - 2x + 14

           = x(x - 7) - 2(x - 7)

           = (x - 2)(x - 7)

    If h(x) = f(x)g(x)

    h(x) = -(3x + 1)(x -2)(x - 7)

    For h(x) ≥ 0

    -(3x + 1)(x - 2)(x - 7) ≥ 0

     $x\leq -\frac{1}{3}$ Or 2 ≤ x ≤ 7

    Therefore, for 2 ≤ x ≤ 7, h(x) ≥ 0

C). If k(x) = $\frac{h(x)}{(x-2)}$

    k(x) = $\frac{-(3x+1)(x-2)(x-7)}{(x-2)}$

    k(x) = -(3x + 1)(x - 7)

    For k(x) = -56

    -(3x + 1)(x - 7) = -56

     3x² -20x - 7 = 56

     3x² - 20x - 63 = 0

     3x² - 27x + 7x - 63 = 0

     3x(x - 9) + 7(x - 9) = 0

     (3x + 7)(x - 9) = 0

     $x=-\frac{7}{3},9$