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3 years ago

Plissss! I really need help

Mathematics

1 answer:

Flura [38]3 years ago

6 0

Answer:

I'll help you if you help me with my most recent question:

Identify the elements of art used and the most prominent or visibe of them and explain. I've attached the image. I'm working on your question and please work on mine.

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A) Write 600 as the product of prime factors.<br> Give your answer in index form.

dlinn [17]

Answer:

3 × 5 × 5 × 2 × 2 × 2

Step-by-step explanation:

Make a factor tree.

But let me explain the above to prove it's correct.

3 × 5 = 15

15 × 5 = 75

75 × 2 = 150

150 × 2 = 300

300 × 2 = 600

Therefore 600 as a product of prime factors is: <u>3 × 5 × 5 × 2 × 2 × 2</u>

4 0

3 years ago

Read 2 more answers

What is the area of this?

11111nata11111 [884]

192
i did that test before

7 0

3 years ago

The graph shows the time and distance Mr. Patel has driven while on a business trip. What is the unit rate in miles per hour he

boyakko [2]

Answer:75. y/x = 75/1 = 75

Step-by-step explanation:

y/x = 75/1 = 75

7 0

3 years ago

Could someone please help with this question

bonufazy [111]

The answer is 7 cause first you multiple 8*35=280 then you dive it by 40 which is
7

6 0

3 years ago

Read 2 more answers

Find the compound interest on Rs. 2000 for one year at the rate of '20%' per annum. If theinterest compounded quarterly.

trasher [3.6K]

Given:

Principal = Rs. 2000

Rate of interest = 20% p.a. compounded quarterly.

Time = 1 year

To find:

The compound interest.

Solution:

Formula for amount:

$A=P\left (1+\dfrac{r}{n}\right)^{nt}$

where,

P = Principal

r = Rate of interest

t= Time

n = number of times interest compounded in an year.

Putting P=2000, r=0.2, n=4 and t=1, we get

$A=2000\left (1+\dfrac{0.2}{4}\right)^{4(1)}$

$A=2000\left (1.05\right)^{4}$

$A=2000\left (1.21550625\right)$

$A=2431.0125$

Now, the compound interest is

$C.I.=A-P$

$C.I.=2431.0125-2000$

$C.I.=431.0125$

Therefore, the compound interest is Rs 431.0125.

3 0

3 years ago

Plissss! I really need help​

Plissss! I really need help