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Sever21 [200]
3 years ago
11

Plissss! I really need help​

Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

I'll help you if you help me with my most recent question:

Identify the elements of art used and the most prominent or visibe of them and explain. I've attached the image. I'm working on your question and please work on mine.

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Julli [10]
Lol hiiiiiiiiiiiiiiiiii
7 0
3 years ago
9x-23=49 what is the second step in this equation?
ladessa [460]

Answer:

Divide both sides by 9.

Step-by-step explanation:

To find the second step of the equation, we actually have to solve parts of the equation until we get to step 2.

Step 1: Add 23 to both sides.

  • 9x - 23 + 23 = 49 + 23
  • 9x = 72

Step 2: Divide both sides by 9.

  • \frac{9x}{9} = \frac{72}{9}
  • x = 8

Therefore, the second step is divide both sides by 9.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

5 0
2 years ago
What is the simplified form of x+3/4+x+2/4
Savatey [412]
Hey there! :D

Since all the terms are being added together, and there is a common denominator with the fractions, we can just add them.

x+x= 2x  3/4+2/4= 5/4

2x+5/4

2x+1.25<== simplest form

I hope this helps!
~kaikers
7 0
3 years ago
Read 2 more answers
A square and rectangle have the same perimeter.
rewona [7]
Perimeter of rectangle:2(length+width):2(13+7)=40
Perimeter of square:4(length of one side):4(x)=40
X=10
7 0
3 years ago
Solve<br><img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D
Nostrana [21]

Answer:

\displaystyle   \begin{cases} \displaystyle  {x} _{1} =  - p \\   \displaystyle x _{2}   =  -  q \end{cases}

Step-by-step explanation:

we would like to solve the following equation for x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}  +  \frac{1}{x}  =  \frac{1}{p  + q + x}

to do so isolate \frac{1}{x} to right hand side and change its sign which yields:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{1}{p  + q + x}  -  \frac{1}{x}

simplify Substraction:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{x - (q + p +  x)}{x(p  + q + x)}

get rid of only x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{  - (q + p )}{x(p  + q + x)}

simplify addition of the left hand side:

\displaystyle  \frac{q + p}{pq}     =  \frac{  - (q + p )}{x(p  + q + x)}

divide both sides by q+p Which yields:

\displaystyle  \frac{1}{pq}     =  \frac{  -1}{x(p  + q + x)}

cross multiplication:

\displaystyle    x(p  + q + x)  =   - pq

distribute:

\displaystyle    xp  + xq +  {x}^{2} =   - pq

isolate -pq to the left hand side and change its sign:

\displaystyle    xp  + xq +  {x}^{2} + pq =  0

rearrange it to standard form:

\displaystyle   {x}^{2} +    xp  + xq  + pq =  0

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

\displaystyle  x( {x}^{} +   p ) + xq  + pq =  0

factor out q:

\displaystyle  x( {x}^{} +   p ) +q (x + p)=  0

group:

\displaystyle  ( {x}^{} +   p ) (x + q)=  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

\displaystyle   \begin{cases} \displaystyle  {x}^{} +   p  = 0 \\   \displaystyle x + q=  0 \end{cases}

cancel out p from the first equation and q from the second equation which yields:

\displaystyle   \begin{cases} \displaystyle  {x}^{}   =  - p \\   \displaystyle x  =  -  q \end{cases}

and we are done!

3 0
3 years ago
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