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Yuki888 [10]
3 years ago
12

A store is advertising a sale with 15% off all prices in the store. Sales tax is 8%. Which equation will correctly determine the

total cost, C, of buying an item with an original price of p, after the discount and sales tax are included? Select all that apply.
Mathematics
2 answers:
ICE Princess25 [194]3 years ago
4 0

Answer: 15%-8%=C

Step-by-step explanation:

docker41 [41]3 years ago
3 0

Answer:

Well, you didnt include answers, but... here's the explanation.

Step-by-step explanation:

Ok so, the sale is 15% off.  As an example, lets use $10 as the original price.  15% off of $10 = 1.5, so we subtract 10 - 1.5 = 8.5.  Now, if the sale tax is 8%, we need to add 8% of 10, which is 0.8 - Now we get our final equation to calculate p, which is 8.5 + 0.8 = P.  8.5 + 0.8 = 9.3, and so the final price after discount AND sales tax are included is $9.3 - Hope this helped.  Mark me as brainliest please :)

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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
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Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

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Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

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a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

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