chile anyways so hehhejjakwkw
Can you take a more clear photo ?
Yea something is not right.if y=6 then you cant solve the system because you end up with x^2-4x-1
g(x) =f(x) +3
given f(x) =3x
i.e. g(x) =3x+3
For F(x) to be same as g(x)
3 must be added to f(x)
i.e. h(x) =3x+3
->h(x)= 3x +3(1)
-> h(x) = f(x) +f(1)
-> h(x) =f(x+1)
Hence Option (a) is your answer...
Hope it helps...
Regards
Leukonov/Olegion
I'm assuming this is what they want? haha