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natka813 [3]
3 years ago
14

A teacher is treating her seventh graders to a pizza party for their successes in class. Each student can have two slices of piz

za or will bring their own lunch. The following Venn Diagram represents the number of students who want either pepperoni pizza, cheese pizza, both, or none. According to the Venn Diagram, how many students want at least one slice of pepperoni pizza?
9
16
25
15

Mathematics
2 answers:
alekssr [168]3 years ago
7 0

Answer:

16

Step-by-step explanation:

As per diagram, 16 students want 2 slices of pepperoni and 9 students want 1 slice of pepperoni pizza.

So 16 students want at least 1 slice of pepperoni

Answer is 16

Kitty [74]3 years ago
3 0

Answer:

25

Step-by-step explanation:

9 had exactly one pepperoni

16 had both pepperoni

9 + 16 = 25 had atleast one pepperoni

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On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi
Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0
3 years ago
Find the probability of this event Enter the answer as a fraction in simplest form, as a decimal, and as a
Step2247 [10]

Answer:

12+12+4+6+26=50

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3 0
3 years ago
Read 2 more answers
What is the similarity ratio of the smaller to the larger similar cylinders?
lbvjy [14]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
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\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{smaller}{larger}\qquad \cfrac{s}{s}=\cfrac{\sqrt{48\pi }}{\sqrt{75\pi }}\implies \cfrac{s}{s}=\cfrac{\sqrt{(2^2)^2\cdot 3}}{\sqrt{5^2\cdot 3}}\implies \cfrac{s}{s}=\cfrac{4\sqrt{3}}{5\sqrt{3}}
\\\\\\
\cfrac{s}{s}=\cfrac{4}{5}
8 0
3 years ago
Read 2 more answers
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krok68 [10]

Answer:

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Step-by-step explanation:

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8 0
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Check my answer please!
Ray Of Light [21]
The answer is C, 4.

you combine like terms and that is the answer you get.

4 0
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