One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel
<h3><u>Solution:</u></h3>
Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.
We have to prove that the lines are parallel.
If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.
Now, the 1st angle will be 1/6 of right angle is given as:
And now, 15 degrees is 11 times smaller than the other
Then other angle = 11 times of 15 degrees
Now, sum of angles = 15 + 165 = 180 degrees.
As we expected their sum is 180 degrees. So the lines are parallel.
Hence, the given lines are parallel
Answer:
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Step-by-step explanation:
Answer: it’s acute
Step-by-step explanation:
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<u><em>Answer:</em></u>sin (C)
<u><em>Explanation:</em></u><u>In a right-angled triangle, special trig functions can be applied. These functions are as follows:</u>
sin (theta) = </span>
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cos (theta) = </span>
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tan (theta) = </span>
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<u>Now, let's check the triangle we have:</u>
<u>We have two options:</u>
<u>First option:</u>5 is the hypotenuse of the triangle
4 is the side adjacent to angle B
Therefore, we can apply the <u>cos function</u>:
cos (B) = </span>
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<u>Second option:</u>5 is the hypotenuse of the triangle
4 is the side opposite to angle C
Therefore, we can apply the <u>sin function</u>:
sin (C) = </span>
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Among the two options, the second one is the one found in the choices. Therefore, it will be the correct one.
Hope this helps :)
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