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d1i1m1o1n [39]
3 years ago
14

Hi how are you my name is

Mathematics
2 answers:
True [87]3 years ago
6 0

Answer:

Leo

Step-by-step explanation:

Kaylis [27]3 years ago
6 0

Answer: Hi I'm Jason I'm good how are you

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Use slopes and y-intercepts to determine if the lines y=5x+5 and 5x−y=−5 are parallel.
GalinKa [24]

Answer: They are not parallel, they are coincident

Step-by-step explanation:

If two lines have the same slope but a different y-intercept, the lines are parallel. If two lines have the same slope and the same y-intercept, the lines are coincident.

We can rewrite 5x−y=−5 adding -5x to both sides and multiplying by -1:

5x - y =-5

5x - y -5x = -5 - 5x (adding -5x to both sides)

-y = -5 - 5x

Multiplying by -1

y = 5x + 5

Both equations look the same so they are coincident. They have the same intercept y=5 and the same slope m=5.

7 0
4 years ago
Pleaseer❤️❤️ help me
defon

Answer:

1)D 2)C 3)A 4)B 5) A

Step-by-step explanation:

1) The area rectangle is 36x^2 -1

We know ,

A= l*b

=36x^2 -1

=(6x)^2 -1

=(6x+1) (6x-2)

This the value of l,b respectively.

So, Perimeter of rectangle is 2(l+b)

P=2(6x+1) + 2(6x-1)

=24x

2)The area of square is 4(x+5)^2

We know,

A=l^2

=4(x+5)^2

=4(x^2 + 10x + 25)

=(2x+10)^2

This is the value of l=2x+10.

So, Perimeter of square is 4l

P=4(2x+10)

=8x+40

3)The fully factorized form is

= -2x^2 + 10x +12

= -2x^2 + 12x -2x +12

= -2x(x-6) -2(x-6)

= -2(x-6) (x+1)

4)The fully factorized form is

=x^4 -81

=(x^2)^2 -9^2

=(x^2 + 9) (x^2 - 9)

=(x^2 + 9) (x^2 - 3^2)

=(x^2 + 9) (x + 3) (x - 3)

5)The fully factorized form is

= 5x^4 - 320

= 5(x^4 - 64)

= 5((x^2)^2 - 8^2)

= 5(x^2 + 8) (x^2-8)

8 0
4 years ago
Write the pair of fractions as a pair of fractions with a common denominator 1/4 and 5/12
zavuch27 [327]

See picture for answer.

4 0
4 years ago
Two bicyclists leave the center of town at the same time. One heads due north and the other heads due west. Later, the two cycli
Ad libitum [116K]
This  situation is represented  in annex. 
From Pythagorean theorem you've got equation:
x^2+(x+5)^2=25 \\ \\ \hbox{From formula} \ \ \ (a+b)^2 = a^2+2ab+b^2: \\ \\ x^2+x^2+10x+25=25 \\ 2x^2+10x=0 \\ \\ \hbox{Factor out} \ \ 2x: \\ 2x(x+5)=0 \\ \\ \hbox{So you've got:} \\ \\ x_1=0 \\ x_2=-5

There isn't any solutions where x>0, so this situation is IMPOSSIBLE.

Did you write correctly this question....?

3 0
3 years ago
Read 2 more answers
Write 1 3/5 as an improper fraction?
CaHeK987 [17]
1 3/5 as an improper fraction is 8/5
8 0
2 years ago
Read 2 more answers
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