This is a concept of momentum. In equation, momentum is the product of force and distance. When a ball is thrown, its force is constant all throughout unless disturbed by an external force. Therefore, force is the constant of proportionality that relates momentum with distance. When you block a ball from a given distance, you would feel the great force on your hand. In order to reduce the force, you have to follow the direction of the force in order to minimize the impact. By doing this, you gradually decrease the momentum of the ball.
Answer:
a) B = 1.99 x 10⁻⁴ Tesla
b) B = 0.88 x 10⁻⁴ Tesla
Explanation:
According to Biot - Savart Law, the magnetic field due to a currnt carrying straight wire is given as:
B = μ₀ I L/4πr²
where,
μ₀ = permebility of free space = 1.25 x 10⁻⁶ H m⁻¹
I = current = 2 A
L = Length of wire = 40 cm = 0.4 m
a)
r = radius of magnetic field = 2 cm = 0.02 m
Therefore,
B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.02 m)²
<u>B = 1.99 x 10⁻⁴ Tesla</u>
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b)
r = radius of magnetic field = 3 cm = 0.03 m
Therefore,
B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.03 m)²
<u>B = 0.88 x 10⁻⁴ Tesla</u>
Answer:
Attention
Explanation:
Hello there, fellow peer! The answer to question is attention. Let's say someone is the control. The behavioral expression is an element of expression, so the control will feel emotions. Subjective Experience is when someone felt the way you feel and they are trying to help you. That is a type of emotion which can lead to empathy for you. This is also not the answer. Physiological Arousal is also not the answer because this is when you can feel what someone else is feeling and you try to give them therapy.
Using the process of elimination, our answer is therefore attention.
Answer:
<em>The force is now 9 times the original force</em>
Explanation:
<u>Coulomb's Law
</u>
The electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Coulomb's formula is:
![\displaystyle F=k\frac{q_1q_2}{d^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%3Dk%5Cfrac%7Bq_1q_2%7D%7Bd%5E2%7D)
Where:
![k=9\cdot 10^9\ N.m^2/c^2](https://tex.z-dn.net/?f=k%3D9%5Ccdot%2010%5E9%5C%20N.m%5E2%2Fc%5E2)
q1, q2 = the particles' charge
d= The distance between the particles
Suppose the distance is reduced to d'=d/3, the new force F' is:
![\displaystyle F'=k\frac{q_1q_2}{\left(\frac{d}{3}\right)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%27%3Dk%5Cfrac%7Bq_1q_2%7D%7B%5Cleft%28%5Cfrac%7Bd%7D%7B3%7D%5Cright%29%5E2%7D)
![\displaystyle F'=k\frac{q_1q_2}{\frac{d^2}{9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%27%3Dk%5Cfrac%7Bq_1q_2%7D%7B%5Cfrac%7Bd%5E2%7D%7B9%7D%7D)
![\displaystyle F'=9k\frac{q_1q_2}{d^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%27%3D9k%5Cfrac%7Bq_1q_2%7D%7Bd%5E2%7D)
![\displaystyle F'=9F](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%27%3D9F)
The force is now 9 times the original force