The linear speed of the ladybug is 4.1 m/s
Explanation:
First of all, we need to find the angular speed of the lady bug. This is given by:
where
T is the period of revolution
The period of revolution is the time taken by the ladybug to complete one revolution: in this case, since it does 1 revolution every second, the period is 1 second:
T = 1 s
Therefore, the angular speed is
Now we can find the linear speed of the ladybug, which is given by
where:
is the angular speed
r = 65.0 cm = 0.65 m is the distance of the ladybug from the axis of rotation
Substituting, we find
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Answer:
the strength of the electric field
The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
<u>Given the following data:</u>
Charge = 
C.
Distance = 0.100 m.
<u>Scientific data:</u>
Coulomb's constant = 
<h3>How to calculate the net force.</h3>
In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
<u>Where:</u>
- r is the distance between two charges.
<u>Note:</u> d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
![F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}](https://tex.z-dn.net/?f=F_%7B13%7D%20%3D%208.988%5Ctimes%2010%5E9%20%5Ctimes%20%5Cfrac%7B%28-2.35%20%5Ctimes%2010%5E%7B-6%7D%20%5Ctimes%20%5B-2.35%20%5Ctimes%2010%5E%7B-6%7D%5D%29%7D%7B0.200%5E2%7D%5C%5C%5C%5CF_%7B13%7D%20%3D%20%5Cfrac%7B0.0496%7D%7B0.04%7D)
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
![F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}](https://tex.z-dn.net/?f=F_%7B13%7D%20%3D%208.988%5Ctimes%2010%5E9%20%5Ctimes%20%5Cfrac%7B%28-2.35%20%5Ctimes%2010%5E%7B-6%7D%20%5Ctimes%20%5B-2.35%20%5Ctimes%2010%5E%7B-6%7D%5D%29%7D%7B0.100%5E2%7D%5C%5C%5C%5CF_%7B13%7D%20%3D%20%5Cfrac%7B0.0496%7D%7B0.01%7D)
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
Read more on charges here: brainly.com/question/14372859
The right answer for the question that is being asked and shown above is that: "d. electrical to electromagnetic." the type of energy transfer is made possible by a nine-volt battery in a calculator is that of d. electrical to electromagnetic<span>
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