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Bogdan [553]
3 years ago
12

Simplify 2.5(0.5 + 0.3) = (-4) + 4.8. Give your answer in decimal form.

Mathematics
1 answer:
postnew [5]3 years ago
7 0

Answer:

is it 1.2 = 0

Step-by-step explanation:

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Explain how to perform a​ two-sample z-test for the difference between two population means using independent samples with sigma
Rom4ik [11]

Answer:

Step-by-step explanation:

In the two independent samples application, it involves the test of hypothesis that is the difference in population means, μ1 - μ2. The null hypothesis is always that there is no difference between groups with respect to means.

Null hypothesis: ∪₁ = ∪₂. where ∪₁ represent the mean of sample 1 and ∪₂ represent the mean of sample 2.

A researcher can hypothesize that the first mean is larger than the second (H1: μ1 > μ2 ), that the first mean is smaller than the second (H1: μ1 < μ2 ), or that the means are different (H1: μ1 ≠ μ2 ). These ae the alternative hypothesis.

Thus for the z test:

    if n₁ > 30 and n₂ > 30

     z = X₁ - X₂ / {Sp[√(1/n₁ + 1/n₂)]}

where Sp is √{ [(n₁-1)s₁² + (n₂-1)s₂²] / (n₁+n₂-2)}

5 0
3 years ago
Suppose his airplane flies in still air at a speed of 420 km/h. One day the wind is blowing strongly at 110 km/h towards the nor
riadik2000 [5.3K]
The answer will be 46,200 Hopes this helps. :)
3 0
3 years ago
PLEASE HELP! PLEASE ANSWER MY QUESTION PLS
andrew-mc [135]

Answer:

Tooth A

Step-by-step explanation:

Since the larger tooth has to be displayed, knowing that no matter how many zeros you add to the end of a decimal, the value of it will stay the same. 0.23 is 1 digit short that 0.195, so if you just add a 0 to 0.23, it make both of them have a digit in the thousandths place. Now it's easier to solve, 0.230>0.195.

Tooth A should be displayed.

8 0
2 years ago
PLSSS HLEPP ME OUTT ITS URGENTTTT​
Tems11 [23]
2.25 days i would assume if they each wat once a day. However there isn’t enough info because we dont know how often they’re eating.
4 0
3 years ago
Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
4 years ago
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