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iren [92.7K]
4 years ago
6

What is the nature of the distance time graph for motion of an object.

Physics
1 answer:
sweet [91]4 years ago
8 0
That kind of depends on the motion of the object.  The graph is drawn in order
to illustrate the nature of the object's motion, and they're all different.  If they
were all the same, then graphs would be boring, and nobody would draw them
anymore.
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dalvyx [7]
The solution for this problem is through this formula:Ø = w1 t + 1/2 ã t^2 
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128 = w1 x 4 + ½ x 4.5 x 5^2 128 = 4w1 + 56.254w1 = -128 + 56.25 4w1 = 71.75w1 = 71.75/4
w1 = 17.94 or 18 rad s^-1 
w1 = wo + ãt 
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wo - initial angular velocity 
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kow [346]

Answer:

The maximum height the pebble reaches is approximately;

A. 6.4 m

Explanation:

The question is with regards to projectile motion of an object

The given parameters are;

The initial velocity of the pebble, u = 19 m/s

The angle the projectile path of the pebble makes with the horizontal, θ = 36°

The maximum height of a projectile, h_{max}, is given by the following equation;

h_{max} = \dfrac{\left (u \times sin(\theta) \right)^2}{2 \cdot g}

Therefore, substituting the known values for the pebble, we have;

h_{max} = \dfrac{\left (19 \times sin(36 ^{\circ}) \right)^2}{2 \times 9.8} = 6.3633894140470403035477570509439

Therefore, the maximum height of the pebble projectile, h_{max} ≈ 6.4 m.

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