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scoundrel [369]
3 years ago
14

A piece of wood is floating in a bathtub. A second piece of wood sits on top of the first piece, and does not touch the water. I

f the top piece is taken off and placed in the water, what happens to the water level in the tub?
A. The water level cannot be determined without additional information.B. The water level remains unchanged.C. The water level rises.D. The water level drops.
Physics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

B

Explanation:

Water level remains unchanged

The first thing to realize is that the buoyancy force is the same as, or equal to the weight of the wood, this same force is also the same as or equal to the weight of the water displaced by the wood. In the two cases, the weight of the wood will be unaffected nonetheless, and thus the water level will remain the same.

Therefore, the answer is B, the water level remains unchanged.

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Read 2 more answers
U NICIUN
Natasha_Volkova [10]
Answer B would be the correct answer for the questions

5 0
3 years ago
Question 1 (1 point)
TiliK225 [7]

Answer:

The resultant velocity of the plane relative to the ground is;

150 kh/h north

Explanation:

The flight speed of the plane = 210 km/h

The direction of flight of the plane = North

The speed at which the wind is blowing = 60 km/h

The direction of the wind = South

Therefore, representing the speed of the plane and the wind in vector format, we have;

The velocity vector of the plane = 210.\hat j

The velocity vector of the wind = -60.\hat j

Where, North is taken as the positive y or \hat j direction

The resultant velocity vector is found by summation of the two vectors as follows;

Resultant velocity vector = The velocity vector of the plane + The velocity vector of the wind

Resultant velocity vector = 210.\hat j  + (-60.\hat j) =  210.\hat j  - 60.\hat j = 150.\hat j

The resultant velocity vector = 150.\hat j

Therefore, the resultant velocity of the plane relative to the ground = 150 kh/h north.

3 0
3 years ago
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