Answer:
The stuntman will not make it
Explanation:
At the bottom of the swing, the equation of the forces acting on the stuntman is:
where:
T is the tension in the rope (upward)
mg is the weight of the man (downward), where
m = 82.5 kg is his mass
is the acceleration due to gravity
is the centripetal force, where
v = 8.65 m/s is the speed of the man
r = 12.0 m is the radius of the circule (the length of the rope)
Solving for T, we find the tension in the rope:
Since the rope's breaking strength is 1000 N, the stuntman will not make it.
Answer:
1989.6Kg
Explanation:
The computation of the mass of the other body is given below:
As we know that
F = G × m1 × m2 ÷ r²
Here the G would have the constant value i.e. 6.67 × 10^-11Nm² / kg².
Now
6.5 × 10^-7N = 6.67 × 10^-11Nm² / kg² × 60Kg × m2 / (3.5m) ²
m2 = (F × r²) / (G × m1)
m2 = (6.5 × 10^-7N × (3.5m) ²) ÷ (6.67 × 10^-11Nm² / kg² × 60Kg)
= 1989.6Kg
Answer:
The pencil is not pulled towards a person due to a very small magnitude of force between them, due to lighter masses.
Explanation:
Let us apply Newton's Law of Gravitation between a person and pencil.
Average Mass of a Normal Pencil = m₁ = 10 g = 0.01 kg
Average Mass of a Person = m₂ = 80 kg
Distance between both = r = 1 cm = 0.01 m (Taking minimal distance)
Gravitational Constant = G = 6.67 x 10⁻¹¹ N.m²/kg²
So,
F = Gm₁m₂/r²
F = (6.67 x 10⁻¹¹ N.m²/kg²)(0.01 kg)(80 kg)/(0.01 m)²
<u>F = 5.34 x 10⁻⁷ N</u>
This Force is very small in magnitude due to the light masses of both objects.
<u>Therefore, the pencil is not pulled towards a person due to a very small magnitude of force between them, due to lighter masses.</u>
The phase of the moon facing the Earth is always the same, which means that the speed of rotation of the moon and the Earth are the same. Because of which the other part of the moon is not visible to the people on Earth.
