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Yuri [45]
3 years ago
10

the temperature fell 10 degrees fahrenheit from 48 degrees to 38 degrees in 12 hrs. how much would the temperature fall over 18

hrs if the pattern continued?
Mathematics
1 answer:
polet [3.4K]3 years ago
8 0
The tempature would fall 15 degrees 10÷12=x x×18= your answer
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An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry ou
Katyanochek1 [597]

Answer:

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

p_v =P(t_{(5)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

Step-by-step explanation:

Data given and notation  

The mean and sample deviation can be calculated from the following formulas:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}

\bar X=29.35 represent the sample mean  

s=1.365 represent the sample standard deviation  

n=6 sample size  

\mu_o =30 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is lower than 30 or no, the system of hypothesis are :  

Null hypothesis:\mu \geq 30  

Alternative hypothesis:\mu < 30  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

P-value  

We need to calculate the degrees of freedom first given by:  

df=n-1=6-1=5  

Since is a one-side left tailed test the p value would given by:  

p_v =P(t_{(5)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

5 0
2 years ago
Help answer ASAPPP 10 points
Musya8 [376]
Time:logs=time:logs
time/logs=time/logs

4hours:6logs=18hours:xlogs
4hours/6logs=18hours/xlogs
4/6=18/x
6/4=18/x
x=27

pick B,C,E
8 0
2 years ago
Read 2 more answers
What type of shape will the reflected figure be?
julsineya [31]
How does your figure look like?
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3 years ago
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What is 6000 x 999897
vlada-n [284]
<span>5999382000 is the answer</span>
3 0
3 years ago
What’s the length of the leg?
AveGali [126]

Answer:

a = 4 cm

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

a² + 3² = 5²

a² + 9 = 25 ( subtract 9 from both sides )

a² = 16 ( take the square root of both sides )

a = \sqrt{16} = 4

3 0
3 years ago
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