Which of these elements has the least attraction for electrons ina chemical bond?(1) oxygen (3) nitrogen(2) fluorine (4) chlorin
2 answers:
The element which gas least attraction for the electrons in chemical bond is.
Further explanation:
Electronegativity:
It is defined as the tendency of an atom to attract the shared electrons in the bond towards itself is known as electronegativity. The more electronegative atom will more attract the bonding electrons towards itself than the less electronegative one. Therefore the electrons will spend more time with the more electronegative atom than an electropositive atom. The electronegative atom will acquire the partial negative charge, and the electropositive atom will acquire a partial positive charge.
Higher the electronegativity value of the element more will be its tendency to accept an electron towards itself.
Electronegativity trends in the periodic table:
<em>Along the period</em>, electronegativity increases due to the increase in the nuclear charge. This results in the strong attraction of electrons.
<em>Down the group</em>, electronegativity decreases due to an increase in the size of elements. This results in lesser attraction between the nucleus and the electron.
The given elements fluorine, oxygen, nitrogen, are present in the same period of the periodic table. Since along the periods the electronegativity decreases, therefore, the order of electronegativity is N<O<F. Among these electronegative elements, nitrogen is an atom with least the electronegativity value.
In the given elements chlorine and fluorine, chlorine has less electronegative value because down the group electronegativity decreases.
Therefore we have two atoms, nitrogen, and chlorine which have lesser electronegative value. Now both nitrogen and chlorine have nearly the same electronegativity value, but since chlorine is larger in size thus its electron is more loosely held by the nucleus. Therefore, the element which gas least attraction for the electrons in chemical bond is chlorine.
Learn more:
1. Which ion was formed by providing the second ionization energy? brainly.com/question/1398705
2. Determine a chemical equation representing the first ionization energy for lithium: brainly.com/question/5880605
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Electronegativity
Keywords: Elements has the least attraction for electrons, chemical bond, oxygen, nitrogen, fluorine, chlorine.
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<u>Answer: </u>The volume of the solution is 85.7 mL
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
We are given:
Molarity of solution = 0.600 M
Given mass of = 12.00 g
We know, molar mass of
Putting values in equation 1, we get:
The rule of significant number that is applied for the problems having multiplication and division:
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.
Hence, the volume of the solution is 85.7 mL
Answer: Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ
Explanation:
To calculate the entalpy, we use the equation:
where,
q = heat absorbed by water = ?
m = mass of water =
c = heat capacity of water = 4.186 J/g°C
= change in temperature =
Sign convention of heat:
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
The heat absorbed by water will be equal to heat released by
To calculate the number of moles, we use the equation:
Given mass = 5.11 g
Molar mass = 120 g/mol
Putting values in above equation, we get:
0.042 moles of releases = 2.8033 kJ
1 mole of releases =
Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ