In the given chemical reaction iron is less electropositive metal and aluminum is more electropositive and behave as a reducing agent also.
<h3>What is electropositivity?</h3>
Electropositivity is the ability of an atom of donation or losing of electrons easily.
From the given chemical reaction it is clear that oxidation state of iron changes from +3 to 0 & of aluminum is from 0 to +3. So in the above chemical reaction aluminum is more electropositive than iron metal. And aluminum is behave as a reducing agent as it helps in the reduction process by providing electrons.
Hence aluminum is electropositive metal and reducing agent, iron is less electropositive.
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2C5H12 + 16O2 —> 10CO2 + 12H2O
2•5=10 C 10=1•10
2•12=24 H 24=2•12
16•2=32 O 32=(10•2)+(1•12)
=20+12
to calculate density you use the equation m/v. Divide the mass by the volume in order to get an object's density.
Mass is how much matter is in an object. Volume is how much space an object occupies. Density is the amount of mass in a volume.
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According to Henderson–Hasselbalch Equation,
pH = pKa + log [Acetate] / [Acetic Acid]
As,
pKa = -log Ka
pKa = -log (1.8 × 10⁻⁵)
pKa = 4.74
So,
pH = 4.74 + log [Acetate] / [Acetic Acid]
4.34 = 4.74 + log [Acetate] / [Acetic Acid]
4.34 - 4.74 = log [Acetate] / [Acetic Acid]
-0.40 = log [Acetate] / [Acetic Acid]
Taking Antilog on both sides,
[Acetate] / [Acetic Acid] = 0.398