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melisa1 [442]
3 years ago
10

3. What effect does dark energy have on the universe?

Chemistry
1 answer:
sladkih [1.3K]3 years ago
4 0
Dark energy and dark matter seem over analyzed, although they are no different than gravity and wind. Dark energy can be the pulling caused by black holes, stars, and large planets. Dark matter also is just the effect of cosmic dust and debris pushed from explosions but also pulling caused by distant gravitational bodies.
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What do the properties of waves moving through aquatic environments tell us about the organisms living in those environments?
pshichka [43]
Assmksksmwmwosmeodmksnsks
7 0
3 years ago
¿Cuál es la molaridad de 275 ml de solución, que se preparó disolviendo 42 g de hidroxido de sodio NaOH en agua?
Dovator [93]
CEYSDINO IS A FILE SPAMMER SHE OR HE USES DIS FILE TO GET YOUR INFORMATION...

8 0
3 years ago
Please help balance this equation <br> _B2Br6 + _HNO3= _B(NO3)3+_HBr
Trava [24]

Answer: B2Br6 + 6HNO3 → 2B(NO3)3 + 6BrH

Equation

B2Br6+HNO3=B(NO3)3+HBr

B=2                                 B=1

BR=6                             BR=1

H=1                                  H=1

N=1                                  N=3

O=3                                 O=9

ANSWER

B2Br6 + 6HNO3 → 2B(NO3)3 + 6BrH

B=2                                 B=2

BR=6                             BR=6

H=6                                  H=6

N=6                                  N=6

O=18                                 O=18

HOPE THIS HELPS

4 0
3 years ago
Compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl2(aq) at standard pressure
Galina-37 [17]

Answer : The correct option is, (1) lower

Explanation :

Formula used for lowering in freezing point :

\Delta T_f=i\times k_f\times m

where,

\DeltaT_b = change in freezing point

k_b = freezing point constant

m = molality

i = Van't Hoff factor

According to the question, we conclude that the molality of the given solutions are the same. So, the freezing point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) The dissociation of KCl will be,

KCl\rightarrow K^++Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(b) The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The freezing point depends only on the Van't Hoff factor. That means higher the Van't Hoff factor, lower will be the freezing point and vice-versa.

Thus, compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl_2(aq) at standard pressure is lower.

4 0
3 years ago
PLEASE HELP ASAP NO LINKS PLEASE
Zarrin [17]

Answer:

gravity

Explanation:

Gravity is the force that pulls us to the surface of the Earth, keeps the planets in orbit around the Sun and causes the formation of planets, stars and galaxies.

Hope this helped!!!

5 0
3 years ago
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