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Alja [10]
4 years ago
12

Answer asap and right plz

Mathematics
1 answer:
Luba_88 [7]4 years ago
6 0
The answer to the question is B
You might be interested in
What is the probability of having 53 Mondays in a leap year?
Ronch [10]

Answer:

1/7

Step-by-step explanation:

There are 52 weeks in a year. Each have one Monday. Leap years have a total of 366 days. There are  7 days of the week. Monday is one of them, so it'll be a 1/7 chance.

5 0
4 years ago
the sum of the digits of a two-digit number is 14. the first digit is 4 less than twice the second digit. what is the number
Blizzard [7]

Answer:

86

Step-by-step explanation:

t = ten's digit    u= one's digit

t + u = 14            t = 2u - 4

In the first equation substitute for t 2u - 4 that we find in the second equation above.

t + u = 14

2u - 4 + u = 14  Combine the u's

3u - 4 = 14  Now add 14 to both sides

3u = 18  Divide both sides by 3

u = 6.  We found the unit's digit, now we will find the ten's unit by plugging in 6 for u in the first equation above.

t + u = 14

t + 6 = 14  Subtract 6 from both sides

t = 8

So, your answer is 86.

5 0
2 years ago
30 POINTS!!!! Select all the products that are negative.
Semenov [28]

Answer:

-4) -9) -4) -2) -6) -6) -6)

7 0
4 years ago
If the area of a rectangle is
igomit [66]

Answer:

255

Step-by-step explanation:

(15x2 - 16x - 15) = 270

(3- 5) = -15

270

-  -15

= 255

7 0
3 years ago
Sid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-d
Papessa [141]

Answer:

21 ways

Step-by-step explanation:

number = 7 digit

5 digit no = 52115

to find out

How many different seven-digit numbers

solution

first we need to place the two missing 3s in the number 52115

we consider here two cases

case 1  the two 3's appear separated (like 532135 or 3521135)  

case 2 the two 3's appear together (like 5332115 or 5211533)  

Case 1 we can see  that number type as _5_2_1_1_5_  

place 3's placeholders show potential locations

( type a ) for  3's  separated we will select 2 of  6 place and place 3 in every location so we do this 6C2  = (15) ways  

and (type b): again use same step as  _5_2_1_1_5_  

here 3s together for criterion and we will select 1 of the 6 place and place both 3s here and there are 6 ways.  

so that here will be 15+6=21 ways

If 3 and 3 are separate so 6C2 = 15  ways

If 3 and 3 are together so there = 6  ways

= 15 + 6 = 21 ways

8 0
3 years ago
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