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egoroff_w [7]
3 years ago
9

Ft-Fg= ma solve for a

Physics
2 answers:
densk [106]3 years ago
8 0
The answer is a= Ft-Fg/m
tensa zangetsu [6.8K]3 years ago
6 0
Ft - Fg = ma   Divide both sides by m
\frac{Ft - Fg}{m} = a   Switch the sides to make it easier to read
a = <span>\frac{Ft - Fg}{m} </span>
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Scorpion4ik [409]

Answer:

so its easier to understand for the reader

Explanation:

4 0
3 years ago
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an object of mass 8 kg is whriled round in a vertical circle of radius 2m with a constant speed of 6m/s .Then the maximum and mi
algol13

Answer:

Maximum Tension=224N

Minimum tension= 64N

Explanation:

Given

mass =8 kg

constant speed = 6m/s .

g=10m/s^2

Maximum Tension= [(mv^2/ r) + (mg)]

Minimum tension= [(mv^2/ r) - (mg)]

Then substitute the values,

Maximum Tension= [8 × 6^2)/2 +(8×9.8)] = 224N

Minimum tension= [8 × 6^2)/2 -(8×9.8)]

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2 years ago
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otez555 [7]

1) 4°C : It has the highest density as shown on the graph.

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7 0
2 years ago
A closed container initially holds 50 monatomic Aparticles that have a combined energy of 480 units. After 100 monatomic B parti
Molodets [167]

Answer:

"8 units" is the appropriate answer.

Explanation:

According to the question,

Throughout equilibrium all particles are of equivalent intensity, and as such the integrated platform's total energy has been uniformly divided across all individuals.

Now,

The total energy will be:

= 480+720

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2 years ago
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Archy [21]

Answer:

Fractional error = 0.17

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F = 112 ± 19 N

Explanation:

Plug in the values to find the force:

F = (3.5 kg) (20 m/s)² / (12.5 m) = 112 N

Find the fractional error:

ΔF/F = Δm/m + 2Δv/v + Δr/r

ΔF/F = 0.1/3.5 + 2(1/20) + 0.5/12.5

ΔF/F = 0.17

Multiply by 100% to find the percent error:

ΔF/F × 100% = 17%

Solve for the absolute error:

ΔF = 0.17 × 112 N = 19 N

Therefore, the force is:

F = 112 ± 19 N

8 0
3 years ago
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