Answer:
1. Speed=0
2. 2.46 s
3.30.1 m
4. 22.0 m
5.1.004 s
Explanation:
We are given that
Initial speed of blue ball, u=24.1 m/s
Height of blue ball from ground y_0=0.5 m
Initial speed of red ball , u'=7.2 m/s
Height of red from ground=y'0=32 m
Gravity, g=
1.When the ball reaches its maximum height then the speed of the blue ball is zero.
2.v=0
Using the formula and substitute the values
Where g is negative because motion of ball is against gravity
3.
Using the formula
4.Time of flight for red ball=3.77-2.9=0.87s
Hence, the height of red ball 3.77 s after the blue ball is 22.0 m.
5.According to question
Hence, 1.004 s after the blue ball is thrown are the two balls in the air at the same height.