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HACTEHA [7]
3 years ago
15

A 9 v battery causes a current of 0.45 a through a resistor. (a) what is its resistance? (b) how many joules of energy does the

battery lose in a minute? j
Physics
1 answer:
aliina [53]3 years ago
7 0
\displaystyle I = \dfrac{u}{R} \Rightarrow R = \dfrac{u}{I} = \dfrac{9 \ V}{0.45 \ A}  = 20 \ \Omega. \newline
P = \dfrac{\Delta uq}{\Delta t} = Iu = 0.45 \ A \cdot 9 \ V = 4.05 \ \dfrac{J}{s} = 14580 \ \dfrac{J}{h} = 14.58 \ \dfrac{kJ}{h}.
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