This would actually represents how the distance expands over the period of time. So, when this shows us that, this person or this thing went 25 miles in 4 hours, this would show us the acceleration of this car and he speed that this car or object would contain.
Answer:
The required angular speed ω of an ultra-centrifuge is:
ω = 18074 rad/sec
Explanation:
Given that:
Radius = r = 1.8 cm
Acceleration due to g = a = 6.0 x 10⁵ g
Sol:
We know that
Angular Acceleration = Angular Radius x Speed²
a = r x ω ²
Putting the values
6 x 10⁵ g = 1.8 cm x ω ²
Converting 1.8 cm to 0.018 m, also g = 9.8 ms⁻²
6 x 10⁵ x 9.8 = 0.018 x ω ²
ω ² = (6 x 10⁵ x 9.8) / 0.018
ω ² = 5880000 / 0.018
ω ² = 326666667
ω = 18074 rad/sec
Answer:
Information from the leading mathematicians was considered "classified".
Explanation:
At the highest point, the tension force is 0, so the only force acting on the sphere is gravity. Sum of forces on the sphere in the centripetal direction:
∑F = ma
mg = mv²/r
v = √(gr)
v = √(9.8 m/s² × 1 m)
v = 3.13 m/s
If the speed is constant, then the linear speed at the lowest point is also 3.13 m/s. Otherwise, we would need to know the tension in the string at that point.
